Chitinase is a protein that breaks down chitin, a primary component of the cell wall in fungi, scales in fish and exoskeletons of arthropods. The activity of chitinase extracted from a plant was shown to be optimum at pH 5. You were tasked to prepare 300 mL of 150 mM buffer solution for further analysis of the extracted chitinase. REAGENTS Ka 2.5M Acetic acid Solid NaOAc•3H2O [136.08g/mol] 1.76 x 10-5 2.5M NH3 Solid NH4Cl [53.49g/mol] 5.6 x 10-10 2.5M Lactic acid Solid sodium lactate [112.06g/mol] 4.0 x 10-5 5 M HCl 5M NaOH What are the moles of the (1) acid and (2) base components, given the following reagents? What is the mass/volume of the components needed to prepare the buffer solution?

Chitinase is a protein that breaks down chitin, a primary component of the cell wall in fungi, scales in fish and exoskeletons of arthropods. The activity of chitinase extracted from a plant was shown to be optimum at pH 5. You were tasked to prepare 300 mL of 150 mM buffer solution for further analysis of the extracted chitinase. REAGENTS Ka 2.5M Acetic acid Solid NaOAc•3H2O [136.08g/mol] 1.76 x 10-5 2.5M NH3 Solid NH4Cl [53.49g/mol] 5.6 x 10-10 2.5M Lactic acid Solid sodium lactate [112.06g/mol] 4.0 x 10-5 5 M HCl 5M NaOH What are the moles of the (1) acid and (2) base components, given the following reagents? What is the mass/volume of the components needed to prepare the buffer solution?

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.5QAP

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You have a solution that contains acetic acid, (CH3COOH or HAc). The concentration of acetic acid in the aqueous solution is 0.35 mol / dm3. Ka = 1.7378 x 10 ^ -5 M a. Calculate the pH of the solution. 15 cm 3 of the acetic acid solution was titrated with sodium hydroxide solution, NaOH (aq), at a concentration of 0.5 mol / dm3 b. Describe how you would proceed to perform a titration of an acid of unknown concentration. What information can be obtained from a titration, describe the different phases. c. How much NaOH will be added when the equivalence point occurs?
The concentration of ammonia in a cleaning product was determined by back titration.Firstly, 10.00 cm3 of the cleaning product was pipetted into a large conical flask,containing 250.00cm3 of 0.50 mol/l HCl to give Solution A.Following a period of reaction and shaking, 50.00cm3 of Solution A was removed anddiluted to 250 cm3 with water in a volumetric flask to give Solution B.20 cm3 samples of Solution B were titrated against 0.05 mol/l Na2CO3 solution, givingan average titre of 12.45 cm3. i) Write equations for the reactions that have taken place.ii) Determine the concentration of NH3 in the original cleaning product in mol/l,g/l, ppm, and % w/v.
For titration for determination of Chloride, 0.05 AgNO3 and NaCl with a 5% (w/v) K2CrO4 indicator, what is the % (w/w) Cl- using the atomic weight for Chlorine. Data below: Primary standard weight 0.1173g , 0.1056g , and 0.1049g Vol of titrant delivered 35.47mL , 31.75mL, and 31.04mL Uknown Chloride mass 0.1527g, 0.1442g, and 0.1337g Vol of titrant delivered 40.00mL ,37.68mL ,and 34.96 mL
In an experiment to determine the concentration of H2SO4 in a brand of toilet cleanser, 10.0 cm3 of the cleanser was first diluted to 250.0 cm3 with distilled water. 25.0 cm3 of the diluted cleanser were titrated with 0.320 mol dm–3 NaOH solution, using methyl orange as indicator.If 29.2 cm3 of NaOH solution is used, what is the concentration of H2SO4 in the undiluted toilet cleanser?a. 2.30 mol dm–3b. 4.60 mol dm–3 c. 9.20 mol dm–3 d. 11.50 mol dm–3
A generic version for Drug X is applying registration to the FDA. For the generic drug to be approved, it must prove bioequivalence with an innovator/originator drug. However, the company registering Drug X is applying for an exemption for in vivo bioequivalence testing. To qualify for this exemption, one of the requirements is to prove that it can be highly soluble in an aqueous buffer of pH 1.2, 4.5, 6.8. As the drug formulator, you need to prepare these buffers to test your sample. 1. For the pH 4.5 buffer, you must use acetic acid and sodium hydroxide: CH3COOH + NaOH → NaCH3COO + H2O The Ka of acetic acid is 1.8 x 10-5. Using the Henderson-Hasselbalch equation, calculate the molar ratio of [conjugate base]/[weak acid] that must be used in preparing the buffer. 0.29 B. 0.57 C. 0.87 D. 1.14 2. The only remaining NaOH in the lab is 100 mL of 1.0 M NaOH solution. Given this amount, how many moles of acetic acid must be used to prepare 1 L of the buffer. 0.088 mol B. 0.175…
To determine the concentration of glucose in the packaged juice industry, 50 mL of sample is analyzed. Analysis of it (and other reducing sugars) was carried out there using triiodide back titration. An excess volume of 75.00 mL of 0.338 M triiodide standard solution in alkaline medium was added to the glucose solution. The resulting solution was acidified and the excess triiodide was titrated with 18.37 mL of standard 0.526 M thiosulfate solution. Calculate is the concentration in ppm in the sample. In alkaline medium: Glucose (C6H12O6) / Gluconate (C6H11O7-), Triiodide (I3- ) / Iodide (I-) In acid medium: Thiosulfate (S2O32-) / Tetrathionate (S4O62-), Triiodide (I3- ) / Iodide (I-)
The amount of iron in a meteorite was determined by a redox titration using KMnO4 as the titrant. A 0.4185 -g sample was dissolved in acid and the liberated Fe3+ quantitatively reduced to Fe2+, using a reductor column. Titrating with 0.0044 M KMnO4 requires 28.76 mL to reach the end point. Determine the %w/w Fe2O3 in the sample of meteorite. (Fe = 55.845 amu, Fe2O3 = 159.69 g/mol
Extraction of DNA involves the use of a 1 M phosphate buffer (1-liter volume) having the hydrogen ion concentration of 6.165950019 x 10-9 M. Three pKa of phosphoric acid are available Concentrated phosphoric acid (85% w/w; Sp. Gr. = 1.70; MW = 98 g/mol) Sodium dihydrogen phosphate monohydrate (MW = 138g/mol) Sodium biphosphate heptahydrate (MW = 268g/mol) Tribasic sodium phosphate monohydrate (MW = 182 g/mol) Sodium hydroxide pellets (40 grams/mol) Question: What is the pH of the solution? (answer in two decimal places) How much of the weak acid component should be used? (Note for answer: Round to the nearest hundredth and include the unit such as "grams or milliliters"; Ex. 100.00 grams or 100.00g for weight & 100.00 milliliters or 100.00 mL for volume) Question: What is the suitable buffer component to be used? (Note for the answer: Separate the two components with “and”; Ex: Ammonia and Ammonium chloride) Question: How much of the salt component should be used?…
A 20 ml aliquot of malonic acid solution was treated with 10.0 ml of 0.25M Ce4+ leading to the reaction CH2(COOH)2 + 6Ce4+ + 2H2O ® HCOOH + 2CO2 + 6Ce3+ + 6H+ After standing for 10 minutes at 60oC, the solution was cooled and the x’ss Ce4+ was titrated with 0.1M Fe2+, requiring 14.4 ml to reach the ferroin end point. Calculate the M of the malonic in the sample.
There are many organic acids and bases in our cells, and their presence modifies the pH of the fluids inside them. It is useful to be able to assess the pH of solutions of acids and bases and to make inferences from measured values of the pH. A solution of equal concentrations of lactic acid and sodium lactate was found to have pH= 3.08. (a) What are the values of pKa and Ka of lactic acid? (b) What would the pH be if the acid had twice the concentration of the salt?
The solubility of borax, which is made up of sodium tetraborate (Na2B4O5(OH)4 8H2O), was analyzed. The dissolution of borax is: Na2B4O5(OH)4 • 8H2O(s) ⇌ 2 Na+(aq) + B4O5(OH)42–(aq) + 8 H2O(l) A 50 mL saturated solution was prepared. After filtration of solution, 5 mL aliquot was transferred to a flask and titrated using 0.432 M HCl. The endpoint was found to be 4.73 mL of the titrant. Tetraborate anion (B4O5(OH)42-) is a weak base which reacts with HCl like the following reaction: B4O5(OH)42–(aq) + 2 H+(aq) + 3 H2O(l) ⇌ 4 H3BO3(aq) What is Ksp expression for the dissolution? What is the tetraborate ions concentration in the filtrate? What is the molar solubility and Ksp of borax if the titration was done at room temperature (298 K)?
The concentration of Cl– in a 300.0-mL sample of water drawn from a fresh water acquifer suffering from encroachment of sea water, was determined by titrating with 0.0516 M Hg(NO3)2. The sample was acidified and titrated to the diphenylcarbazone end point, requiring 6.18 mL of the titrant. Report the concentration of Cl–in parts per million

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REAGENTS	Ka
2.5M Acetic acid	Solid NaOAc•3H2O [136.08g/mol]	1.76 x 10-5
2.5M NH3	Solid NH4Cl [53.49g/mol]	5.6 x 10-10
2.5M Lactic acid	Solid sodium lactate [112.06g/mol]	4.0 x 10-5
5 M HCl	5M NaOH