Choose the answer which presents the chemical formulas for two substances in order of decreasing melting point (highest melting point first) and gives a valid reason for this order. a) CO > C(diamond) because CO has a triple bond and stronger dispersion forces. b) C6Cl6 > C6H6 due to ionic bonding in C6Cl6 not present in C6H6. c) CaO > ScN due to ionic forces in CaO not present in ScN. d) Al > H2O due to strong metallic bonding in Al, versus weaker hydrogen bonding in H2O. e) CF4 > XeF4 due to ionic bonding in CF4 not present in XeF4.
Choose the answer which presents the chemical formulas for two substances in order of decreasing melting point (highest melting point first) and gives a valid reason for this order. a) CO > C(diamond) because CO has a triple bond and stronger dispersion forces. b) C6Cl6 > C6H6 due to ionic bonding in C6Cl6 not present in C6H6. c) CaO > ScN due to ionic forces in CaO not present in ScN. d) Al > H2O due to strong metallic bonding in Al, versus weaker hydrogen bonding in H2O. e) CF4 > XeF4 due to ionic bonding in CF4 not present in XeF4.
World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter14: Liquids And Solids
Section: Chapter Questions
Problem 3A
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Choose the answer which presents the chemical formulas for two substances in order of decreasing melting point (highest melting point first) and gives a valid reason for this order.
a) CO > C(diamond) because CO has a triple bond and stronger dispersion forces.
b) C6Cl6 > C6H6 due to ionic bonding in C6Cl6 not present in C6H6.
c) CaO > ScN due to ionic forces in CaO not present in ScN.
d) Al > H2O due to strong metallic bonding in Al, versus weaker hydrogen bonding in H2O.
e) CF4 > XeF4 due to ionic bonding in CF4 not present in XeF4.
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