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Asked Dec 5, 2019
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Combining 0.256 mol Fe,O, with excess carbon produced 12.3 g Fe.
Fe,0, + 3C → 2 Fe + 3 CO
What is the actual yield of iron in moles?
actual yield:
mol
What is the theoretical yield of iron in moles?
theoretical yield:
mol
What is the percent yield?
percent yield:
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Combining 0.256 mol Fe,O, with excess carbon produced 12.3 g Fe. Fe,0, + 3C → 2 Fe + 3 CO What is the actual yield of iron in moles? actual yield: mol What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? percent yield:

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Expert Answer

Step 1

Given,

Moles of Fe2O3 = 0.256 mol

Mass of Fe produced = 12.3 g

The actual yield of iron in moles can be calculated as :

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Molar mass of Fe = 55.8 g/mol 12.3 g Mass Actual moles of Fe = 0.22 mol 55.8 g/mol Molar mass

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Step 2

The balanced chemical reaction is given as:

Fe2O3 + 3 C → 2 Fe + 3 CO

The theoretical yield of iron in moles can be calculated as :

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1 mol Fe2O3 produces 2 mol Fe 2 mol Fe .. 0.256 mol Fe2O3 produces x 0.256 Fe2O3 1 mol Fe203 = 0.512 mol Fe

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Step 3

Therefore, the percent yield ...

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Actual yield × 100% % yield Theoritical yield 0.22 mol % yield x 100% 0.512 mol % yield = 42.97 %

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