Example: Compute the available strength of the compression member shown in the figure. Two angles, 5 x 3x 1/2, are oriented with the long legs back-to-back (2L5 × 3 ×12 LLBB) and separated by 38 inch. Theeffective length KL is 16 feet, and there are three fully tightened intermediate connectors. A36 steel is used.For each componentFor 5 x 3 ×1/2 A=3.75 in?1 = 9.43 in* I, = 2.55 in*aaaa=1.58= 0.824 r. = 0.64216'x = 0.746 j =1.74ortgen Biçimli Ekran AlırFor A36 steelF = 36 ksi E = 29000ksiCompute the flexural buckling strenath for the X-axis:

flexural buckling strength for the x axis, KxL/rx = 1.5816(12) =121.5 Fe=π2E(KL/r)2…

Answered: Compute the available strength of the…

Engineering

Civil Engineering

Compute the available strength of the compression member shown in the figure.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.12.2P

See similar textbooks

Related questions

Q: A beam cross section is shown. If the beam is subjected to a moment of 400N.m, the maximum bending…

Q: The cross-sectional dimensions of the beam shown in the figure are a = 4.8 in., b = 6 in., d = 4.0…

Q: 1. Determine the force in each member of the truss loaded as shown below. Indicate whether the…

A: Calculate the reactions at support A and D: Negative value of the RD reaction indicates that its…

Q: A simply supported beam of span 4 m carries a concentrated load Pin kN acting downward at distance…

Q: Determine the largest weight W which can be supported by the two wires shown. The stresses in wires…

Q: A cantilever beam BD rests on a simple beam AC as shown below. Both beams are of the same material…

A: It can be solved using solving for moments along both the axis.

Q: PROBLEM 01 REFER TO FIGURE 01, DETERMINE THE INTERNAL FORCES ACTING ON THE FOLLOWING MEMBERS: (STATE…

Q: A simple beam on a 10 ft span supports a uniform load of intensity 800 lb/ft (see figure). The beam…

A: Solution: Given Data: Uniform load intensity=800 lb/ftBeam member=4×11.5 inEw=1.5×106 psiEs=30×106…

Q: The composite beam shown in the figure is simply supported and carries a total uniform load of 50…

Q: Problem (2): By Inspection (no calculation), identify the zero-force members in Figure (a) and…

Q: The square column is under compression due to a 50 KN load as shown in the figure. The member is…

Q: A simply supported beam of span 4 m carries a concentrated load p acting downward at distance 1.5 m…

Q: A 4-T crane is used to lift a 3m x 1.2m x 200mm pre-cast panel. A spreader beam is needed to ensure…

A: Lc = 1200mm Bc = 200mm Hc = 3000mm Densityc = 25KN/m3

Q: Determine the largest weight W which can be supported by the two wires shown. The stresses in wires…

Q: A steel rod composed of two parts (AD and DB), which have different cross-sectional area, is fixed…

Q: A boxed wooden shape is used to support the loads shown on the beam. The dimensions of the shape are…

Q: The square column is under compression due to a 50 KN load as shown in the figure. The member is…

A: Given: The load P is 50 kN. The allowable compressive stress is 6.8 MPa.

Q: The cross-sectional area of each member of the truss is 1.8 sq.in. Calculate the stress in ksi in…

A: Given:- The cross-sectional area of each member of the truss = 1.8 in2 The magnitude of the point…

Q: he maximum elastic stress in tension is 100 MPa and in compression is 150 MPa. All measurements are…

A: FInd Neutral axis :y⏜=A1y1-A2y2A1-A2y⏜=80×1201202-π4×80240+3080×120-π4×802y⏜=49FInd moment of…

Q: S A flanged shape is used to support the loads shown on the beam in figure below The dimensions of…

A: Find maximum tension and compression bending stress at any location along the beam.

Q: The members of the truss are 25mmx50mm in cross section. Determine the maximum load P that can be…

Q: 2. For the beam and loading shown, determine the maximum flexural stress (compression and tension)…

Q: Q2. For the truss system given in Figure Q2, knowing that the maximum allowable tensile stress is…

A: Detailed solution below in image formate. Hope it will help you. Good luck.

Q: Determine the maximum compressive and tensile bending stresses of the beam shown, cross-section of…

A: Determine the maximum compressive and tensile bending stresses of the beam shown, cross-section of…

Q: Two vertical forces are applied to a beam of the cross-section shown. Determine (a) the maximum…

A: To determine: maximum tensile and compressive bending stresses bending and shear stress a bending…

Q: For the beam shown in the figure below, find the maximum tensile and compressive flexural stresses.…

A: step 1-

Q: The square column is under compression due to a 50 KN load as shown in the figure. The member is…

A: Given data:- load,P=50 kN Allowable compressive stress at the joint = 6.8 MPa To find It is asked to…

Q: A simply supported beam of span 4 m carries a concentrated load P acting downward at distance 1.5 m…

Q: Determine the stress induced of member AF and BC. Indicate if Compression or Tension.

Q: For the beam shown, a. Determine the maximum flexural stresses in compression and tension. b.…

Q: The beam shown is made of a nylon for which the allowable stress is 24MPa in tension and 31MPa in…

Q: If the temperature increases by 95°F, calculate the increase in stress for the steel segment shown.…

Q: An aluminum bar having a cross-sectional area of 160 mm² carries the axial loads as shown in the…

Q: A simply supported beam of span 4 m carries a concentrated load Pin kN acting downward at distance…

Q: The round bar shown in the figure has steel, brass and aluminum sections. Axial loads are applied at…

A: Draw the FBD of each section such that each part is in equilibrium. Then using the definition of…

Q: A simply supported beam of span 4 m carries a concentrated load Pin kN acting downward at distance…

Q: Calculate the bending stresses at top and bottom fibers of a simply supported beam and loaded as…

A: bending stress distribution with some assumption . the plane section remain plane after bending and…

Q: Consider the truss shown in (Figure 1). AE is constant. Suppose that F = 3.2 kN. Part A Determine…

Q: For the beam shown, the working stresses are 48 MPa in tension, 140 MPa in compression, and 30 MPa…

A: The maximum load that a structure can safely carry. It's the load at which the structure is in a…

Q: An aluminum bar having a cross-sectional area of 160 mm carries the axial loads as shown in the…

Q: As shown in the figure below, determine the internal loadings at points A,B and. Consider the…

Q: If the temperature increases by 90°F, calculate the increase in stress for the steel segment shown.…

Q: The cross-sectional area of each member of the truss is 1.8 sq.in. Calculate the stress in ksi in…

A: When the beam has loaded the stress caused by stretching forces is known as Tension force. The…

Q: A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented…

Q: A wooden beam is fabricated by bolting together three members, as shown in Figure below. The…

Q: Q2. For the truss system given in Figure Q2, knowing that the maximum allowable tensile stress is…

A: Support reactions∑Fx=0 ; Ax+X2=0Ax=-100 KN =100 KN ( towards left )∑Fx=0 ;…

Q: Determine the force in each member of the truss loaded as shown below. State if the members are in…

A: Consider the figure. Here, T is tension and C is compression.

Q: An aluminum bar having a cross-sectional area of 160 mm? carries the axial loads as shown in the…

Concept explainers

Members with compression and bending

Compression members are structural elements that carry compressive axial force. They are the vertical members of a building that support beams and their design, which is governed by buckling and strength. Columns are known as struct or compression members, which are subjected to compressive forces. These members provide stiffness to the building and avoid any imperfection regarding the transfer of axial load. For instance, webs in a truss, braces in a framed structure, tiers, and so on.

Question

Example: Compute the available strength of the compression member shown in the figure. Two angles, 5 x 3
x 1/2, are oriented with the long legs back-to-back (2L5 × 3 ×12 LLBB) and separated by 38 inch. The
effective length KL is 16 feet, and there are three fully tightened intermediate connectors. A36 steel is used.
For each component
For 5 x 3 ×1/2 A=3.75 in?
1 = 9.43 in* I, = 2.55 in*
a
a
a
a
=1.58
= 0.824 r. = 0.642
16'
x = 0.746 j =1.74ortgen Biçimli Ekran Alır
For A36 steel
F = 36 ksi E = 29000ksi
Compute the flexural buckling strenath for the X-axis:

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0.a) Determine the design tensile strength of the section based on yielding of the gross area.b) Determine the critical net area of the connection shown.
A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. a) Determine the allowable tensile strength of the section based on tensile rupture of the net area.b) Determine the allowable tensile strength of the section based on yielding of the gross area.
A PL 38 X 6 tension member is welded to a gusset plate as shown. The steel is A36 (Fy = 36ksi, Fu = 58ksi). a. The design strength, Pu based on gross area b. The design strength, Pu based on effective area PL % x 6 3/8" 6" Cross Sectional area of PL3/8x6 a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answer
An A36 tension member shown in the figure is connected with three 19 mm diameter bolts. Dia. Of bolt hole = 22 mm. 50, 100 100 99.45 T- 50.55 100 Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm2 y = 50.55 mm Fy = 248 MPa Fu = 400 MPa a. Determine the design strength due to yielding in the gross section. (kN) b. Determine the allowable strength due to yielding in the gross section. (kN) c. Determine the design strength due to fracture in the net section. Use U = 0.85. (kN)
The lap joint in the figure is fastened by four 20 mm Ø A325X bolts. Calculate the maximum safe load P that can be applied if the plates are 25 mm thick A-36 steel Use ASD. 4 @ 40 mm P 2 @ 60 mm P
7 7a 7b 7c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is structural tubing however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? The section is 8" x 8" x 7.94 mm thick: Use Fy=248 MPa: E=200,000 MPa AISC wall thickness Ix 106 S x 103 Jx 103 mm4 mm3 mm4 rx =ry Area Ag (mm2) mm Designation Weight/m 8x8 7.94 47.36 6,039 79.25 37.84 371.99 60.35 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) 8x8 14.29 80.61 10,258 76.2 59.52 585.02 99.06 8x8 72.7 9,290 76.96 54.53 539.13 90.32 8x8 9.53 56.09 7,161 78.48 44.12 432.62 70.76 mm 12.7 Zx 103 mm3 437.53 714.48 650.57 512.92
Question 4 Complete the table below for the steel sections shown. All sections are bending about their horizontal axis. Section Location hep Ney Slenderness (show calculations) of element bf Flange te ld ++ tw be = 800 mm Web tf = 20 mm d = 1440 mm tw = 16 mm Grade 300, heavily 入。= Whole Asp= Asy= welded plates section br Flange tr d Web bf = 800 mm te = 20 mm d = 1420 mm tw = 16 mm Grade 300, heavily welded plates 入。= Whole Asp= Asy= section
TENSION MEMBERS: THE SINGLE 200 X 10 mm STEEL PLATE IS CONNECTED TO A 12 mm THICK STEEL PLATE BY FOUR 16 mm DIAMETER RIVETS AS SHOWN IN THE FIGURE. THE RIVETS USED ARE A502 GRADE 2, HOT DRIVEN RIVETS. THE STEEL IS ASTM A36 WITH Fy = 248 MPa AND Fu = 400 MPa. DETERMINE THE VALUE OF P. a. P BASED ON TENSION OF GROSS AREA b. P BASED ON TENSION OF NET AREA c. P BASED ON BEARING OF PROJECTED AREA d. P BASED ON SHEAR RUPTURE (BLOCK SHEAR)
A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the critical net area of the connection shown. Determine the design tensile strength of the section based on yielding of the gross area.
1. A36 steel (Fy=36Ksi, Fu=58Ksi) is used for the tension member shown in the figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL % x14 2" 5" 2" 2. The tension member is a PL3/8 × 6 of A242 steel (Fy=50Ksi, Fu=70Ksi). It is connected to a 3/8-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in the figure below. Determine the nominal block shear strength of the tension member. in
The given angle bar L125x75x12 with Ag = 2,269 sq.mm. is connected to a gusset plate using 20 mm diameter bolts as shown in the figure. Using A36 steel with Fy = 248 MPa and Fu = 400 MPa, determine the following: 2. Determine the nominal tensile strength of the 12 mm thick, A36 angle bar shown based on: a. Gross yielding b. Tensile rupture Bolts used for the connection are 20 mm in diameter. O O O O O O O Effective net area of the tension member if the shear lag factor is 0.80. Select the correct response: 1,516.1 1,354.4 1,431.2 1,221.6
A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the design tensile strength of the section based on tensile rupture of the net area. Determine the allowable tensile strength of the section based on yielding of the gross area.