Consider 1.00 mol of a monatomic ideal gas for which Cv=3/2 R. The gas is subjected to a thermodynamic cycle composed of the following three steps: 1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step, the volume remains constant at 10.0 L. 2) Isobaric expansion from a pressure of 0.100 atm and 10.0 L (B) to a final volume of 100. L (C). 3) Isothermal compression from point C back to point A. Thermodynamic Cycle A 1 0.9 0.8 0.7 0.6 0.5 1 0.4 0.3 3 0.2 0.1 2 10 20 30 40 50 60 70 80 90 100 Volume (L) What is the change in internal energy for the system in step 2? a) b) c) d) -1370 J e) 1370 J OJ 13.5 J -13.5 J Pressure (atm)

Consider 1.00 mol of a monatomic ideal gas for which Cv=3/2 R. The gas is subjected to a thermodynamic cycle composed of the following three steps: 1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step, the volume remains constant at 10.0 L. 2) Isobaric expansion from a pressure of 0.100 atm and 10.0 L (B) to a final volume of 100. L (C). 3) Isothermal compression from point C back to point A. Thermodynamic Cycle A 1 0.9 0.8 0.7 0.6 0.5 1 0.4 0.3 3 0.2 0.1 2 10 20 30 40 50 60 70 80 90 100 Volume (L) What is the change in internal energy for the system in step 2? a) b) c) d) -1370 J e) 1370 J OJ 13.5 J -13.5 J Pressure (atm)

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.91E: The Dieterici equation of state for one mole of gas is p=RTe-aVRTV-b Where a and b are constants...

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