Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through theclosed surface.LLWe need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux:Фпet 3 Ф1 + Ф2 + Фз + Фхут,+Øxz+@yzThe flux through surface 1 is: 0,=0.The flux through surface 2 is: O2 =The flux through surface 3 is: 03 =The flux through the surface on the xy plane is: 0The flux through the surface on the xz plane is: OxzThe flux through the surface on the yz plane is: O%3DTaking the algebraic sum, the net electric flux through the cube is: Onet =111

flux through surace 1, Φ1=0flux through surace 2, Φ2=E→.S→=EL2cos0=EL2flux through surace 3,…

Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. L L We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: Фрet 3 Ф1 + Ф2+ Фз + Фху + Ф xz + Фуz The flux through surface 1 is: O1 = 0. 111

Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. L L We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: Фрet 3 Ф1 + Ф2+ Фз + Фху + Ф xz + Фуz The flux through surface 1 is: O1 = 0. 111

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 25P: A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The...

See similar textbooks

Similar questions

Find the electric flux through a rectangular area 3 cm x 2 cm between parallel plates where there is a constant electric field of 30 N/C for the following orientations of the area: (a) parallel to the plates, (b) perpendicular to the plates, and (c) the normal to the area making a 300 angle with the direction of the electric field. Note that this angle can also be given as 180o + 30o.
A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux through the square, when the normal to it makes the following angles with electric field: (a) 30(, (b) 90(, and (c) 0(. Note that these angles can also be given as 1800 + .
In free space, let D = 8xyz4ax + 4x2z4ay + 16x2yz3 az pC/m2.Find the total electric flux passing through the rectangularsurface z = 2, 0 < x < 2, 1 < y < 3, in the az direction. Find Eat P(2, −1, 3).
A point charge qq is at the point x=0,y=0,z=0.x=0,y=0,z=0. An imaginary hemispherical surface is made by starting with a spherical surface of radius RR centered on the point x=0,y=0,z=0x=0,y=0,z=0 and cutting off the half in the region z<0.z<0. The normal to this surface points out of the hemisphere, away from its center. Calculate the electric flux through the hemisphere if (a) q=8.00 nCq=8.00 nC and R=0.100 m;R=0.100 m; (b) q=−4.00 nCq=−4.00 nC and R=0.100 m;R=0.100 m; (c) q=−4.00 nCq=−4.00 nC and R=0.200 m;.
If the electric field is given by 6i+3j+4k calculate the electric flux through a surface of area 20 units lying in y-z plane.
Consider a plane surface in a uniform electric field as in the Figure , where d=15 cm and Theta=70 . If the net flux through the surface is 6.00 Nm2/C, find the magnitude of the electric field
The figure shows a Gaussian surface in the shape of a cube with edge length 1.60 m. What are (a) the net flux through the surface and (b) the net charge qenc enclosed by the surface ifthe electric field in the region is in the positive y direction and has a magnitude that is given by E = 3.93y N/C? What are (c) the net flux and (d) net enclosed charge if the electric field is in the xy plane and has components Ex = -4.66 N/C and Ey = (6.79 + 3.93y) N/C?
A uniform electric field of magnitude E=435 N/C makes an angle of θ= 65.0 ° with a plane surface of area A=3.50m² as in the figure below. What is the electric flux through the this surface?
Gauss’s Law Find the flux through the top, left, and right sides of a cube of side 0.5 m when placed in a horizontal uniform electric field of 8.0 N/C directed to the right. Calculate the electric flux for each of the closed surfaces a, b, c, and d if ?1 = 5 ??, ?2 = −8 ??, ?3 = −3 ??, ?4 = −8 ??, ?5 = 4 ??, ?6 = 7 ??, ?7 = 5 ??, and ?8 = −5 ??.
A square 10 cm long is in a region where there exists a uniform 2.0 kN/C electric field normal to the surface of the square. Evaluate the electric flux?
Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: The flux through surface 1 is: . The flux through surface 2 is: . The flux through surface 3 is: . The flux through the surface on the xy plane is: . The flux through the surface on the xz plane is: . The flux through the surface on the yz plane is: . Taking the algebraic sum, the net electric flux through the cube is: .
A non-uniform electric field given by E =(6.0)i +(5.0y)j is in that space of a cube with side length 2.0 mWhat is the electric flux at the bottom surface?