Consider a cube with edge length Limmersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface.We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux:Onet -01+02 +03+0xyThe flux through surface 1 is: 0-0.The flux through surface 2 is: 02-The flux through surface 3 is: O3The flux through the surface on the xy plane is: OxyThe flux through the surface on the xz plane is: OxzThe flux through the surface on the yz plane is: OyzTaking the algebraic sum, the net electric flux through the cube is:net1111

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Consider a cube with edge length Limmersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: ®net =®1+®2+®3 +®»y+®xz+®yz The flux through surface 1 is: 0 -0. The flux through surface 2 is: ®2- The flux through surface 3 is: 0,- The flux through the surface on the xy plane is: 0 The flux through the surface on the xz plane is: ®2- The flux through the surface on the yz plane is: Oyz" Taking the algebraic sum, the net electric flux through the cube is: @net 111

Consider a cube with edge length Limmersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: ®net =®1+®2+®3 +®»y+®xz+®yz The flux through surface 1 is: 0 -0. The flux through surface 2 is: ®2- The flux through surface 3 is: 0,- The flux through the surface on the xy plane is: 0 The flux through the surface on the xz plane is: ®2- The flux through the surface on the yz plane is: Oyz" Taking the algebraic sum, the net electric flux through the cube is: @net 111

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 25P: A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The...

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A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux through the square, when the normal to it makes the following angles with electric field: (a) 30(, (b) 90(, and (c) 0(. Note that these angles can also be given as 1800 + .
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Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: The flux through surface 1 is: . The flux through surface 2 is: . The flux through surface 3 is: . The flux through the surface on the xy plane is: . The flux through the surface on the xz plane is: . The flux through the surface on the yz plane is: . Taking the algebraic sum, the net electric flux through the cube is: .
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