*same question*the reaction would have a:cant determine from the given informationnegativezeropositive Consider the combustion of methane.CH4 (9) + 2 02(g) → CO2(g) +2 H20(g)The reaction would have avAS.Why? Consider the combustion of methane.CH(9) + 2 O2(g) — СО-(9) + 2 H:0(9)The reaction would have avAS.JAS.Why?V --The moles of gas increase.The number of moles are the same in reactants and products.The moles of gas decrease.The moles of reactant decreases.The moles of product increases.The moles of gas remain constant.Calculate thefor the following processI P iumpCID II IC pu es.

Answered: Image /qna-images/answer/194ebc5c-638b-46bf-bc59-d93191ed4b1d.jpg

Answered: Consider the combustion of methane. CH4…

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Consider the combustion of methane. CH4 (9) + 2 O2(g) → CO2(g) +2 H2O(g) The reaction would have a vAS. Why?

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter20: Chemistry Of Selected Transition Elements And Coordination Compounds

Section: Chapter Questions

Problem 42QRT

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Question

*same question*

the reaction would have a:

cant determine from the given information

negative

zero

positive

Consider the combustion of methane.
CH4 (9) + 2 02(g) → CO2(g) +2 H20(g)
The reaction would have a
vAS.
Why?

Consider the combustion of methane.
CH(9) + 2 O2(g) — СО-(9) + 2 H:0(9)
The reaction would have a
vAS.
JAS.
Why?
V --
The moles of gas increase.
The number of moles are the same in reactants and products.
The moles of gas decrease.
The moles of reactant decreases.
The moles of product increases.
The moles of gas remain constant.
Calculate the
for the following process
I P iumpCID II IC pu es.

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