Consider the four-bus sample system in the figure wherein line reactance indicated are in pu. Treat this as a simplified power flow problem where line resistances are considered negligible and the magnitude of all the four bus voltages are specified to be 1.0 pu. Find the value of reactive power supplied by generator 4 (QG4). JO.15 J02 0.15 J0.1 wl-1.0 Real Demand Reactive Demand Real Generation Reactive Bus Generation Po- 2.0 Pa = 1.0 Pos = 1.0 Po= 2.0 Co = 05 Con = 10 P=? Pe=0.0 Pa40 Pa= 0.0 Qej (unspecified) Qez (unspecified) Qes (unspecified) Qa (unspecified) 1. 2. 3. Qo =04 4. 0.8388 pu -32.17 pu 1.16117 pu 34.17 pu

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter13: Continuous Systems; Waves
Section: Chapter Questions
Problem 13.14P
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Consider the four-bus sample system in the figure wherein line reactance indicated are in pu. Treat this as a
simplified power flow problem where line resistances are considered negligible and the magnitude of all the
four bus voltages are specified to be 1.0 pu. Find the value of reactive power supplied by generator 4
(QG4).
"Ml- 1.0
J0.15
J02
0.15
J0.1
1.0
Real
Demand
Reactive
Demand
Real
Generation
Reactive
Bus
Generation
Qa, (unspecified)
Qez (unspecified)
Qes (unspecified)
Qa (unspecified)
Po= 2.0
Pa= ?
Pa-0.0
Pa4.0
Pa = 0.0
1.
2.
Po 1.0
Co = 1.0
3.
Pos = 1.0
Po= 2.0
Qo= 1.0
4.
0.8388 pu
-32.17 pu
1.16117 pu
34.17 pu
Transcribed Image Text:Consider the four-bus sample system in the figure wherein line reactance indicated are in pu. Treat this as a simplified power flow problem where line resistances are considered negligible and the magnitude of all the four bus voltages are specified to be 1.0 pu. Find the value of reactive power supplied by generator 4 (QG4). "Ml- 1.0 J0.15 J02 0.15 J0.1 1.0 Real Demand Reactive Demand Real Generation Reactive Bus Generation Qa, (unspecified) Qez (unspecified) Qes (unspecified) Qa (unspecified) Po= 2.0 Pa= ? Pa-0.0 Pa4.0 Pa = 0.0 1. 2. Po 1.0 Co = 1.0 3. Pos = 1.0 Po= 2.0 Qo= 1.0 4. 0.8388 pu -32.17 pu 1.16117 pu 34.17 pu
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