Construct a Fibonacci number pattern that involves square roots. Both sides of the equation should be equal and one side should use Fibonacci numbers ex.. F(n+2)=F(n)+F(n+1), where n is 3 F(3+2)=F(3)+F(3+1) F5=F3+F4 5=2+3 5=5
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I AM NOT ASKING FOR COMPUTER CODES. THIS IS ADVANCED MATH ONLY.
Construct a Fibonacci number pattern that involves square roots. Both sides of the equation should be equal and one side should use Fibonacci numbers
ex.. F(n+2)=F(n)+F(n+1), where n is 3
F(3+2)=F(3)+F(3+1)
F5=F3+F4
5=2+3
5=5
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- Use following series to do the given task; 135 79 11 13 15 1719 21 23 25 27 29 31 ... Given the number N of odd numbers in a certain line, your task is to determine the sum of the last three numbers of that line. For example N = 5 means, the third line, the last three numbers are 13, 15 and 17. The summation of these three numbers is 45. InputThe first line tells the number of test cases. From the next line, the input is a sequence of lines, one odd number N (1 < N <1000000000) per line. OutputFor each input line write the sum of the last three odd numbers written in that line of series with N numbers.In the example below, the sum of the fourth powers of each digit that forms the 4-digit numbers gives the number itself: 1634 = 14 + 64 + 34 + 44 8208 = 84 + 24 + 04 + 84 9474 = 94 + 44 + 74 + 44 And sum of these numbers is 1634 + 8208 + 9474 = 19316. Find the sum of all numbers that can be written as the sum of the fifth forces of their numbers. (P.s.: You have to done it by C++)Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Sample Input 0:5 20011014 Sample Output 0:1 1 Explanation 0:The best way to jump from square 1 to square 5 is by jumping 4 squares. That requires only 1 jump.In fact, that is the only solution, thus the second output is 1. Sample Input 1:6 3010100123 Sample Output 1:2 2 Explanation 1The best sequence is to jump 2 squares to square 3 then 3 squares to end in square 6.This is one solution. The other solution is to jump from 1 -> 3 -> 5 -> 6. These are the only two solutions, therefore the second output is 2. Sample Input 2:7 2000110037 Sample Output 2:-1 0 Explanation 2:It is impossible to reach square 7 with the specified jump values. The actual…
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- For arbitrary a and b,c % m = (a b) % mc % m = [(a % m) (b % m)] % mUsing this mathematical property, you can iterate 1 to the exponent, recalculating each time by multiplying the current modulus value with the last.Here is the pseudocode:1 Set value = 1, current exponent = 0.2 Increment current exponent by 1.3 Set value = (base value) mod modulus until current exponent is reached exponentExample: Base: 4, Exponent: 3, Modulus: 54ˆ3 % 5 = 64 % 5 = 4value = (lastValue x base ) % modulus:value = (1 x 4) % 5 = 4 % 5 = 4value = (4 x 4) % 5 = 16 % 5 = 1value = (1 x 4) % 5 = 4 % 5 = 4write javascript code ?The Problem A Zeckendorf number is defined for all positive integers as the number of Fibonacci numbers which must be added to equal a given number k. So, the positive integer 28 is the sum of three Fibonacci numbers (21, 5, and 2), so the Zeckendorf number for k = 28 is three. Wikipedia is a satisfactory reference for our purposes for more details of the Zeckendorf and Fibonacci numbers. In both cases, you do not need to read the entire Wikipedia entry. Your assignment is to write two ARM assembly language functions which calculate Zeckendorf and Fibonacci numbers. Zeck function The first function, which should be named zeck, receives an integer parameter in register zero. This will be the variable k we discussed above. Your code should return the Zeckendorf number for k in register zero when complete. If the parameter k is zero, return zero. If the parameter k is negative, return minus 1. If the parameter k is too large to calculate, return minus 1. Fib function The other function,…Correct answer will be upvoted else downvoted. How about we call a positive integer n customary if in the decimal documentation every one of its digits are something very similar. For instance, 1, 2 and 99 are conventional numbers, however 719 and 2021 are not normal numbers. For a given number n, track down the number of common numbers among the numbers from 1 to n. Input The main line contains one integer t (1≤t≤104). Then, at that point, t experiments follow. Each experiment is characterized by one integer n (1≤n≤109). Output For each experiment output the number of common numbers among numbers from 1 to n.
- Use C++ to program a system that lets people guess a random number between 506 and 783 twice. The guesser must know if the number is correct. If not, then they must know how much higher or lower their guess is from the randomly selected number.Here is my question that my professor gave to me as a homework from my algorithm's class.Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion/memoization. Make sure ALL test cases return expected outputs. Sample Input 04 412340123 Sample Output 013715 Explanation 0You are given the sequence 1,2,3,4.F0 = A0 = 1F1 = A1 + F0 = 2 + 1 = 3F2 = A2 + F1 + F0 = 3 + 3 + 1 = 7F3 = A3 + F2 + F1 + F0 = 4 + 7 + 3 + 1 = 15 The actual code def solve(k,a): MOD = 1000000007 # compute and return answer here q, n = list(map(int,input().rstrip().split(" ")))a = [int(input().rstrip()) for i in range(n)]outs = []for i in range(q): k = int(input().rstrip()) outs.append(solve(k,a))print("{}".format("\n".join(list(map(str,outs)))))