Note: Solve using c++ Write a recursive function to get count of a specific character in given string or array of characters. Prototype of Function: int getCharCount(const char* ptr, char c) Input: const char* ptr=” wavelength”, char c=’e’ Output: 2 (as ‘e’ occurs two times in the “wavelength”)
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Note: Solve using c++
Write a recursive function to get count of a specific character in given string or array of
characters.
Prototype of Function: int getCharCount(const char* ptr, char c)
Input: const char* ptr=” wavelength”, char c=’e’
Output: 2 (as ‘e’ occurs two times in the “wavelength”)
Step by step
Solved in 3 steps
- IN C++, with pre an d post pseudocode please Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function. For the recursive function - define one other helper…Implement a recursive C++ function which takes a character (ch) and a positive integer (n) and prints thecharacter ch, n times on the screen. The prototype of your function should be:void printChar (char ch, int n)For example, calling printChar('*',5) should display ***** on screen.Note: There should NOT be any loop in your function.Please IN C++ Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function. For the recursive function - define one other helper function (IsPrimeRecur) which…
- Note: Solve using c++ programming Write a recursive function to get count of unique characters in given string or array of characters.Prototype of Function: int getUniCharCount(const char* ptr,const char* current)Input: const char* ptr=”wavelength”Output: 9c++ Write a recursive function that, given two strings, returns whether the first string is asubsequence of the second. For example, given hac and cathartic, you should return true, but givenbat and table, you should return false.Implement a recursive C++ function which takes an array of integers (arr) and the starting (start) andending (end) indices of a portion (part) of this array, and returns the index of thelargest element present in that portion of array arr. The prototype of your function should be:int findLargest (int* arr, int start, int end) For example, the function call findLargest(arr,3,8)should determine and return the index of the largest element present in the array arr between the indices 3and 8 (both inclusive)
- Need some help with this c++ recursive function: Write the function int countEights(int n). Inside the function, compute recursively (no loops) the count of the occurrences of 8 as a digit inside the parameter n. Except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). Here are some examples: countEights(8) returns 1 countEights(818 returns 2 countEights(8818) returns 4Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…Need help with this c++ recursive function: Write the function starCrossed() which computes (recursively, with no loops) a new string where identical characters that are adjacent in the original string are separated from each other by a "*". Here are some examples: starCrossed("hello") returns "hel*lo" starCrossed("xxyy") returns "x*xy*y" starCrossed("aaaa") returns "a*a*a*a"