Construct pedigree charts using the inheritance of hemophilia in figure 92 (page 113). This is X-linked inheritance so you are required to label XX for females and XY for males. The gene responsible for the trait is represented by the superscript which should be specified in the legend. Father hashemophilia XYMother is not a caerierFather does notMother is a carrierof the hemophilia gene XXof the hemophillia gene XXhave hemophila XY50% chancesons will havehemophilia XYs0% chancedaughters will be a carrierot the hemophilla gene XX0% chancesons will havehemophilia XY100% chancedeughters will be a carrierof the hemophila gene XXCaner of theHermaphia geneKeyDoes nethaveHemophiliaCamer of theHemophiin geneKeyHas HemophilaDoes not haveHan HemophiliaabFig. 92. Inheritance of hemophilia or bleeder's disease (a) when motheris a carrier, and (b) when father has the condition.

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Description: Construct pedigree charts using the inheritance of hemophilia in figure 92 (page 113). This is X-linked inheritance so you are required to label XX for females and XY for males. The gene responsible for the trait is represented by the superscript whi

Pedigree chart is a family tree helps to understand the inheritance of a particular trait or disease…

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Construct pedigree charts using the inheritance of hemophilia in figure 92 (page 113). This is X-linked inheritance so you are required to label XX for females and XY for males. The gene responsible for the trait is represented by the superscript which should be specified in the legend.

Construct pedigree charts using the inheritance of hemophilia in figure 92 (page 113). This is X-linked inheritance so you are required to label XX for females and XY for males. The gene responsible for the trait is represented by the superscript which should be specified in the legend.

Health Safety And Nutrition F/Young Child

9th Edition

ISBN:9781305144767

Author:MAROTZ

Publisher:MAROTZ

Chapter5: The Infectious Process And Environmental Control

Section: Chapter Questions

Problem 3CS

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Astigmatism and polydactyly are dominant over normal vision and finger traits. Sickle-cell anemia onthe other hand, is an overdominant lethal trait due to its recessive genes (ss). Individuals with this traitdie prematurely. Heterozygotes (Ss), however, have some RBCs that sickle while others remainnormal, thus, not lethal. They are referred to as sickle-trait carriers. A polydactylous, normal-visioned, brown-eyed man with wavy hair has a nonpolydactylous, blue-eyed mother. He proposed marriage to a nonpolydactylous, astigmatic, blue-eyed, and curly-hairedlady whose mother has normal vision. However, the lady is worried about the proposal since sickle-cell anemia has been known to run in both their families. a. Is there a genetic basis for her worry? Explain. b. If it turned out that the lady is a carrier and the man has normal RBC, what would be their COMPLETE genotypes? Male genotype:_________________________________Female genotype: ______________________________ c. Based on their…
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