Convert to LEGV8 int main() int set1[5]; int set2[5]; int total=0; set1[0] = 1; for(int i=1; i<5; i++) { set1[i] = set1[i-1] + 2; } set2[0] = 2; for(int j=1; j<5; j+t) { set2[j] = set2[j-1]+ 2; for(int k-0; k<5; k++) { total += set1[k] * set2[
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convert this code and explain each line and what it does/ what it corresponds to. Also do NOT use ADDI. You can use terms such as LSL,MOV, ADD,LDUR,STUR... etc.
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- java getDup accepts an array and returns an int. If there is any element is duplicated, the method counts how many of those present in the array. Example : getDup(["1","2","aa"',"1"]) returns:2 ("1" is duplicated and there are two "1"s so return is 2) class Main { public static int getDup(String[] r) { } public static void main(String[] args) { Scanner in = new Scanner(System.in); String [] strs = new String[in.nextInt()]; for(int i=0; i < strs.length; i++) { strs[i] = in.next(); } System.out.println(getDup(strs)); } } hint: you will need a nested array the will run on the array we get from the method argument. inside the nested loop you will need to check if the main array element is equal to the currentNrite a program in Java that reads 10 integers and store them in AN ArrayList. Then, do the following: ) Print the ArrayList in the reverse order b) Sort the ArrayList, and display the data after sorting c) Print the largest and the smallest element in the ArrayListIn java Develop a function that accepts an array and returns true if the array contains any duplicate values or false if none of the values are repeated. Develop a function that returns true if the elements are in decreasing order and false otherwise. A “peak” is a value in an array that is preceded and followed by a strictly lower value. For example, in the array {2, 12, 9, 8, 5, 7, 3, 9} the values 12 and 7 are peaks. Develop a function that returns the number of peaks in an array of integers. Note that the first element does not have a preceding element and the last element is not followed by anything, so neither the first nor last elements can be peaks. Develop a function that finds the starting index of the longest subsequence of values that is strictly increasing. For example, given the array {12, 3, 7, 5, 9, 8, 1, 4, 6}, the function would return 6, since the subsequence {1, 4, 6} is the longest that is strictly increasing. Develop a function that takes a string…
- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…Computer Science Java Program Write a program in Java that takes in a user-submitted file that is a grid of 0s and 1s. Represent the grid as a two-dimensional array. Write a program that: a. computes the size of a group when a square in the group is given b. computes the numbers of different groups c. lists all groups Example: userInput.txt: 0 0 0 0 0 0 0 0 0 10 0 0 1 1 0 0 0 0 10 0 0 0 0 0 0 0 0 00 0 0 0 1 0 0 1 0 00 0 0 1 0 0 0 1 0 00 0 0 0 0 0 0 1 1 00 0 0 0 1 1 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 0 The program should output three things: The size of the group in which location specified by the user belongs. then if the user enters 1,2 the answer is 0 1,4 the answer is 2 3,4 the answer is 1 4,7 the answer is 4 The number of each size group Size Count 2 3 1 List of each group’s locations 1: (0,9) (1,9) 2: (1,3) (1,4) 3: (3,4) 4: (3,7) (4,7) (5,7) (5,8) 5: (4,3) 6: (6,4) (6,5)in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…
- Q2. Write a java program to perform the following task: a) Create a collection ArrayList<String> for Customer class b) Add 5 elements into ArrayList c) Display the element at index 4 d) Display all the elements in the ArrayList using for-each loop e) Remove the values at index 2 f) Add “cst2” in location 2. g) Check if st2 existing inside the collection.import java.util.ArrayList;import java.util.Arrays; public class PS07A{/*** Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical…Modify the quick sort implementation in the textbook to sort the array using pivot as the median of the first, last, and middle elements of the array. Add the modified quick sort implementation to the arrayListType class provided (arrayListType.h). Ask the user to enter a list of positive integers ending with -999, sort the integers, and display the pivots for each iteration and the sorted array. Main Function #include <iostream>#include "arrayListType.h"using namespace std; int main(){ arrayListType<int> list;int num;cout << "Line 8: Enter numbers ending with -999" << endl;cin >> num; while (num != -999){list.insert(num);cin >> num;} cout << "Line 15: The list before sorting:" << endl;list.print();cout << endl; list.selectionSort();cout << "Line 19: The list after sorting:" << endl;list.print();cout << endl; return 0;} Header File (arrayList.h) Including images #include <iostream>#include <cassert>…
- in java Integer numElements is read from input, representing the number of integers to be read next. Then, the remaining integers are read and stored into array valuesArray. For each element in valuesArray that is divisible by 9, assign the element with the element's current value plus 1. Ex: If the input is: 3 81 99 30 then the output is: Original values: 81 99 30 New values: 82 100 30 Note: (x % 9 == 0) returns true if x is divisible by 9. 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 for (i=0; i<valuesArray.length; ++i) { valuesArray[i] =scnr.nextInt(); } System.out.print("Original values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); /* Your code goes here */ System.out.print("New values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); } }using java programming int a[] = {5,10,4,20,1,7}; 1- search for the smallest element in array 2-if you found the smallest element in the array :swap the first element with the smallest elementComplete this code in Java import java.util.Scanner; import java.util.ArrayList; public class SET { ArrayListlist; int length; public SET(); { list=new ArrayList<>(10); length=0; } public SET(int cap) { list=new arrayList<>(cap); length=0; } public int getLength() { return length; } } public class SetApplication { public static void main(String[] args) { SET st=new SET(); System.out.println(st.getLength()); } }