d and e 11.21 Repair and replacement costs of water pipes. Refer to theIHS Journal of Hydraulic Engineering (September 2012)H2OPIPE Study of water pipes, Exercise 11.12 (p. 622). Recall that ateam of civil engineers used regression analysis to estimatey = the ratio of repair to replacement cost of commercialpipe. The independent variable in the regression analysiswas x = the diameter (in millimeters) of the pipe. Datafor a sample of 13 different pipe sizes are provided inthe table, followed by a Minitab simple linear regressionprintout.Diameter (mm)RatioH20PIPE801006.586.977.397.611251502002507.787.928.203003508.424008.604505008.979.316009.479.72700Source: Based on ISH Journal of HydraulicEngineering, Volume 18, Issue 3, pp. 241-251.Copyright: September 2012.a. Find the least squares line relating ratio of repairto replacement cost (y) to pipe diameter (x) on theprintout.b. Locate the value of SSE on the printout. Is there an-other line with an average error of 0 that has a smallerSSE than the line, part a? Explain.c. Interpret, practically, the values r and ß, .d. Use the regression line to predict the ratio of repairto replacement cost of pipe with a diameter of800 millimeters.e. Commentthe reliability of the prediction,onpart d.Regression Analysis: RATIO versus DIAMETERAnalysis of VarianceAdj ss10.8067 10.806710.8067 10.8067Adj MS F-Value P-Value0.0000.000SourceDF221.20RegressionDIAMETER11221.20Error110.53740.0489Total1211.3441Model SummaryR-sg R-sq (adj) R-sq (pred)94.8340.221034 95.26%92.09%CoefficiontsSE Coef T-Value P-Value55.2914.87TermCoefVIFConstantDIAMETER6.6780.0047860.1210.0003220.0000.000 1.00Regression EquationRATIO = 6.678 + 0.004786 DIAMETER

From the given printout, the least squares line is RATIO=6.678+0.004786 DIAMETER.

Answered: d. Use the regression line to predict…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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d. Use the regression line to predict the ratio of repair to replacement cost of pipe with a diameter of 800 millimeters. e. Comment on the reliability of the prediction, part d.