Question
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Describe how you would prepare each of the following aqueous solutions.

A)Give the mass of the solute and the volume of the solvent for 1.40 L of 0.110 M (NH4)2SO4 solution, starting with solid (NH4)2SO4.

B) Give the mass of the solute and mass of the solvent for 230 g of a solution that is 0.70 m in Na2CO3, starting with the solid solute.

C) Give the mass of the solute and mass of the solvent for 1.30 L of a solution that is 16.0 % of Pb(NO3)2 by mass (the density of the solution is 1.16 g/mL), starting with solid solute.

D)Give the volume of the solute and volume of the solvent for a 0.50 M solution of HCl that would just neutralize 4.5 g of Ba(OH)2 starting with 6.0 M HCl.

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Step 1

The term molarity of a solution  refers to the ratio of number of moles of the solute to the total volume of the solution in liters. It has the units moles/liter or simply (M).The molarity of a solution is denoted by the symbol ‘M’ and can be find out using the general formula :

To calculate the number of moles, the ratio of Mass of the solute to that of molar mass of the solute is taken an it is given by the formula as shown below . It is denoted by the symbol ‘n’.

Step 2

Molality of a solution refers to the ratio of number of moles of solute per kilogram of the solvent. The SI unit of molality is mol/kg  and is given by the formula:

Step 3
• In the given question (A) , Molarity of the ammonium sulfate solution is given to be 0.110 M

Now , we know

In order to make 0.110 M solution of 1.40 L of (NH4)2SO4 solution we need to dissolve 20.32 gm of the given salt and make up the volume wi...

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