Determine if a Z-test, or a T-test should be performed. 3) A researcher would like to determine if college students get less than 8 hours of sleep per night on average. From a survey of 200 adult college students, the mean number of hours of sleep that a student gets per night was 7.58 hours with a sample standard deviation of 1.2 hours. What test should be performed: z-test or t-test 4) According to a certain credit card company the average credit card debt for all of their customers is $4500 with a standard deviation of $700. From a random sample of 50 of their customers, the average debt was $4250. What test should be performed: z-test or t-test
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- A sample of 27 account balances of credit company showed a mean of customer balance of 6,000, but the marketing manager claimed that the mean balance for the population was 5,558. The marketing manager did NOT have the population standard deviation, but the sample standard deviation was found to be 320. Use the p-value approach to conduct a full hypothesis test (all steps) that can be used to determine whether the mean of all account balances is significantly different from 5,558. Let a=.10The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1900 pounds and a standard deviation of 95 pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, M, of the cables is now greater than 1900 pounds. To see if this is the case, 100 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1906 pounds. Can we support, at the 0.10 level of significance, the claim that the population mean breaking strength of the newly-manufactured cables is greater than 1900 pounds? Assume that the population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below.A large midwestern public university admits students into its MBA program based on, among other criteria, their GMAT score. The university's MBA program website states that an applicant must have a minimum score of 500 on the GMAT exam to be admitted to the program. To verify the program's adherence to this policy, the records for a sample of 172 current MBA students admitted to the program were examined. Records for these MBA students revealed a mean GMAT score of 485 with a standard deviation of 15.92. Assuming a .05 level of significance, use Excel and MegaStat to answer the following questions to determine whether or not this policy is being enforced. a. State the hypotheses for this analysis. b. Specify the decision rule. c. Calculate the test statistic and p-value. d. Is the GMAT score policy being enforced? Explain your answer using the decision rule, test statistic, and p-value.
- A sample of 19 account balances of a credit company showed a mean customer balance of $4,350, but the marketing manager claimed that the mean balance for the population was $4,225. The marketing manager did NOT have the population standard deviation, but the sample standard deviation was found to be $300. Use the p-value approach to conduct a full hypothesis test (all steps) that can be used to determine whether the mean of all account balances is significantly different from $4,225. Let α = .05. To help you go through the steps of hypothesis testing, follow these prompts: The null hypothesis is The alternative hypothesis is I will use a (choose 1: t / z) in my formula because I have calculated the value of t (or z) to be I have used t (or z) to get the value of p (most likely from a chart or computer printout). My p value is Alpha, which is given in the problem, is When I compared p to alpha, p is (choose 1: greater than/less than) alpha. Because of this, I know I should…The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1950 pounds and a standard deviation of 50 pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, μ , of the cables is now greater than 1950 pounds. To see if this is the case, 90 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1964 pounds. Can we support, at the 0.10 level of significance, the claim that the population mean breaking strength of the newly-manufactured cables is greater than 1950 pounds? Assume that the population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the…The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1750pounds and a standard deviation of 50 pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, μ, of the cables is now greater than 1750 pounds. To see if this is the case, 90 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1756 pounds. Can we support, at the 0.05 level of significance, the claim that the population mean breaking strength of the newly-manufactured cables is greater than 1750 pounds? Assume that the population standard deviation has not changed.Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. A. Find the value of the test statistic and round to 3 or more decimal places. (I have posted a picture of an example problem and the…
- The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1800 pounds and a standard deviation of 95 pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, μ, of the cables is now greater than 1800 pounds. To see if this is the case, 70 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1829 pounds. Can we support, at the 0.10 level of significance, the claim that the population mean breaking strength of the newly-manufactured cables is greater than 1800 pounds? Assume that the population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. a. State the null hypothesis H0 and the alternative hypothesis H1. b. Find the value of the test statistic. Round to three or more decimal…A recent study compared the time spent together by single- and dual-earner couples. According to the records kept by the wives during the study, the mean amount of time spent together watching television among the single-earner couples was 61 minutes per day, with a standard deviation of 15.5 minutes. For the dual-earner couples, the mean number of minutes spent watching television was 48.4 minutes, with a standard deviation of 18.1 minutes. At the .01 significance level, can we conclude that the single-earner couples on average spend more time watching television together? There were 15 single-earner and 12 dual-earner couples studied.A student at a four-year college claims that the mean enrollment at four-year colleges is higher than a two-year colleges in the United States. Two surveys are conducted. Of the 35 two-year college is surveyed, the main enrollment was 5,068 with a standard deviation of 4,777. Of the 35 four-year colleges surveyed, the main enrollment was 5,466 with a standard deviation of 8,191. Test to claim at 5% level of significance. What is the question/claim to be tested in symbols the hypothesis is Ho: Ha: which hypothesis matches the claim test objective is to reject or support level of significance a=.05 type of test (left, right, two-tailed) the applicable test to be applied is (2-sampZTEST/2-sampTTEST, 2-propZTEST) calculate the applicable test to be applied is (2-sampZTEST/2-sampTTEST, 2-propZTEST) calculate the applicable test statisticz or t= p-value= compare p-value to a (eg. p-value greater than or less than a) decision (reject Ho/Failed to reject) evidence (enough/not…
- A study of seat belts use involved children who were hospitalized after motor vehicle crashes. For a group of 123 children who were wearing seatbelt, the number of days in intensive care units has a mean of 1.2 days and a standard deviation of 1.77 days. For a group of 290 children who were not wearing a seatbelt, the number of days spent in ICU has a mean of 1.89 days and a standard deviation of 2.06 days. a) Use a 0.05 significance level to test the claim that children wearing seatbelt have a lower mean length of time in ICU than the mean of children not wearing seat belts. b) Construct a confidence Interval appropriate to the hypothesis testAccording to the AAA Foundation for Traffic Safety’s American Driving Survey, U.S. drivers spend, on average, 51 minutes behind the wheel each day. A researcher believes this is an overstatement. To investigate, a random sample of 75 drivers were selected. The study revealed that the mean time behind the wheel for the sample of 75 drivers was 46.4 minutes with a standard deviation of 18.8 minutes. Is there convincing evidence that the mean time behind the wheel for all U.S. drivers is less than 51 minutes? Use α = 0.01.A recent study compared the time spent together by single- and dual-earner couples. According to the records kept by the wives during the study, the mean amount of time spent together watching television among the single-earner couples was 61 minutes per day, with a standard deviation of 15.5 minutes. For the dual-earner couples, the mean number of minutes spent watching television was 48.4 minutes, with a standard deviation of 18.1 minutes. At the 0.01 significance level, can we conclude that the single-earner couples on average spend more time watching television together? There were 15 single-earner and 12 dual-earner couples studied. Hint: For the calculations, assume the single-earner as the first sample. Is this a one-tailed or a two-tailed test? multiple choice 1 One-tailed test. Two-tailed test. State the decision rule. (Round your answer to 3 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal…