Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. 239 Pu + 6" 94 134 Xe 54 + 40 103 Zr + 3n Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 10° m/s 1 amu = 1 g/mol = 1.66 x 1027 kg 1 MeV = 1.60 x 10-13 J Note: mass defect = total mass of products - total mass of reactants Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.
Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. 239 Pu + 6" 94 134 Xe 54 + 40 103 Zr + 3n Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 10° m/s 1 amu = 1 g/mol = 1.66 x 1027 kg 1 MeV = 1.60 x 10-13 J Note: mass defect = total mass of products - total mass of reactants Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter19: Nuclear Chemistry
Section: Chapter Questions
Problem 56AP
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Transcribed Image Text:Determine the change in energy (in kJ/mol) of the given nuclear fission reaction.
239 Pu + 6"
94
134 Xe
54
103
+
40
Zr + 3n
Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol
Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu
Speed of light = 3.00 x 10° m/s
1 amu = 1 g/mol = 1.66 x 1027
kg
1 MeV = 1.60 x 10-13
Note: mass defect = total mass of products - total mass of reactants
Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.
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