Determine the change in specific entropy, in kJ/kg K, of CO2 as an ideal gas undergoing a process from T, = 300 K, P, = 1 bar to T, = 1420 K, p2 = 5 bar.Additional informations°1 = 1.70203 kJ/kg-Ks°2 = 3.37901 kJ/kg-K1.215 kJ/kg.°CO 1.215 kJ/kg.KO 1.190 kJ/kg.KO 1.373 kJ/kg.K

Given:T1=300 KP1=1 bar =100 KPaT2=1420 KP2=5 bar =500 KPa

Determine the change in specific entropy, in kJ/kg K, of CO2 as an ideal gas undergoing a process from T, = 300 K, P = 1 bar to T2 = 1420 K, p2 = 5 bar. Additional information s°, = 1.70203 kJ/kg-K s°2 = 3.37901 kJ/kg-K 1.215 kJ/kg.°C

Determine the change in specific entropy, in kJ/kg K, of CO2 as an ideal gas undergoing a process from T, = 300 K, P = 1 bar to T2 = 1420 K, p2 = 5 bar. Additional information s°, = 1.70203 kJ/kg-K s°2 = 3.37901 kJ/kg-K 1.215 kJ/kg.°C

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.

Question

Determine the change in specific entropy, in kJ/kg K, of CO2 as an ideal gas undergoing a process from T, = 300 K, P, = 1 bar to T, = 1420 K, p2 = 5 bar.
Additional information
s°1 = 1.70203 kJ/kg-K
s°2 = 3.37901 kJ/kg-K
1.215 kJ/kg.°C
O 1.215 kJ/kg.K
O 1.190 kJ/kg.K
O 1.373 kJ/kg.K

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