# Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen.Determine the empirical formula for a compound that is 70.79 carbon, 8.91 hydrogen, 4.59 nitrogen, and 15.72 oxygen.C17H27NO3C18H27NO2C18H27NO3C17H26NO3

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Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen.
Determine the empirical formula for a compound that is 70.79 carbon, 8.91 hydrogen, 4.59 nitrogen, and 15.72 oxygen.
C17H27NO3
C18H27NO2
C18H27NO3
C17H26NO3

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Step 1

Determination of empirical formula

Lets say we have 100 g as total mass (take percentage as grams)

step 1: divide each percentage by its atomic mass

C = 70.79 g/12 g/mol = 6 mol

H = 8.91 g/1 g/mol = 8.91 mol

N = 4.59 g/14 g/mol = 0.33 mol

O = 15.72 g/16 g...

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