Determine the enthalpy change, AHrxm, for the following reaction using the information below. P4O10(s) + 6PCI5(g) → 10C13PO(g) P4(s) + 6Cl;(g) → 4PCI;(8) Pa(s) + 50z(g) → P4010(s) AH = -2967.3 k]/mol PCI:(8) + Cl(g) → PCls(8) PCb(g) + ½02(8) → Cl;PO(g) AH=-285.7 kJ/mol AH = -1225.6 kJ/mol AH = -84.2 k]/mol
Determine the enthalpy change, AHrxm, for the following reaction using the information below. P4O10(s) + 6PCI5(g) → 10C13PO(g) P4(s) + 6Cl;(g) → 4PCI;(8) Pa(s) + 50z(g) → P4010(s) AH = -2967.3 k]/mol PCI:(8) + Cl(g) → PCls(8) PCb(g) + ½02(8) → Cl;PO(g) AH=-285.7 kJ/mol AH = -1225.6 kJ/mol AH = -84.2 k]/mol
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
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Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...
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Determine the enthalpy change, AHrpm, for the following reaction using the information
below.
P4010(s) + 6PCI5(g) → 10C1;PO(g)
P4(s) + 6C12(g) → 4PCL(3) AH = -1225.6 k]/mol
Pa(s) + 50z(g) → P4010(s) AH =-2967.3 k]/mol
PCI:(8) + Cl2(g) → PCI5(8) AH = -84.2 kJ/mol
PCls(g) + ½02(8) → Cl;PO(g) AH=-285.7 kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4d03f0d-d3de-4ad9-bc51-313e59eb76cf%2F60354baa-255f-4692-9ce2-f64fd9ebf95e%2Fskfw9as_processed.png&w=3840&q=75)
Transcribed Image Text:4-
Determine the enthalpy change, AHrpm, for the following reaction using the information
below.
P4010(s) + 6PCI5(g) → 10C1;PO(g)
P4(s) + 6C12(g) → 4PCL(3) AH = -1225.6 k]/mol
Pa(s) + 50z(g) → P4010(s) AH =-2967.3 k]/mol
PCI:(8) + Cl2(g) → PCI5(8) AH = -84.2 kJ/mol
PCls(g) + ½02(8) → Cl;PO(g) AH=-285.7 kJ/mol
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