Determine the following: Percent passing and Particle Size Distribution Curve Effective Size Coefficient of Gradation Coefficient of Uniformity and determine the grain size distribution according to: USDA System AASHTO System USCS System
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A: Given Percentage of passing on sieve no 200 = 72 Percentage of passing on sieve no 4 = 90
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A: For soil AA: D10=0.09 D30=0.11 D60=0.13 Cu=0.13/0.09=1.44<6
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A: Following is the given soil distribution: Gravel- 20% Sand- 15% Silt- 20% Clay- 45%
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Q: Given a grain-size distribution and Atterburg limits below: The soil is classified as:
A: Step1:Look at the % passing through sieve no 200=30<50%⇒COARSE GRAINED SOILStep2:Look at the %…
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Q: <0.002 0.002-0.05 0.05-2.0 (%) (%) (%) A 15 45 40 В 15 60 25 C 35 40 25 D 10 30 60
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- Mechanical analysis on four different samples designated as A, B. Cand D were carried out in a soil laboratory. The results of tests are given below. Hydrometer analysis was carried out on sample D. The soil is non-plastic. Sample D. liquid limit w 42, plastic limit = 24, plasticity index = 18 Classify the soils per the Unified Soil Classification System. Samples A ASTM Sieve Percentage finer than Designation 63.0 mm 100 93 20.0 mm 64 76 6.3 39 100 65 20 mm 600 212 63 A 20 24 98 59 12 90 54 5 9. 47 100 2 34 95 23 69 46 2 4 31 Samples A,BandC 10 60 20 Sand Coarse jo medium Coles (>76.2 mm) Clay Silt Gravel Fine 0.001 0.01 0.075 0.1 10 100 Particle size (mun) Figure Ex. 3.21 Percentage finerThe table below shows the laboratory results of the sieve analysis of a sample. The soil has a liquid limit of 35% and plasticity limit of 9%. Determine the following: a) Plot the grain size curve. b) Classify the soil according to SIZE (mm) WEIGHT RETAINED (gms.) 0.25 18.96 USCS 0.149 33.18 c) Classify the soil according to 0.074 45.03 AASHTO 0.052 54.51 d) Classify the soil according to 0.02 42.66 USDA 0.01 11.85 0.004 4.74 0.001 4.74 PAN 21.33 Page 1 | 1 Q + -A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic limit =12% U.S. Sieve Size Percentage Passing 3/8 in. 100.0 No. 4 76.5 No. 10 60.0 No. 40 39.7 No. 200 15.2 Classify the soil sample by the USCS classification system.
- QUESTION 2 a. The results given in Table 1 were obtained in a particle size distribution test for soil sample received in the laboratory. Table 1 US Sieve No. Size Opening(mm) Weight Retained(g) 4 4.75 0 10 2.0 18.5 20 0.85 53.2 40 0.425 90.5 60 0.25 81.8 100 0.150 92.2 200 0.075 58.5 Pan - 26.5i. Determine the percentage passing each sieve and plot the particle size distribution curve. ii. How much fine-grained soils are in the sample ? iii. Determine the amount of gravel and sand in the sample ? iv. Determine D10, D30, and D60 from the grain-size distribution curve. v. Calculate the uniformity coefficient, Cu. vi. Calculate the coefficient of gradation, Cc. vii. Describe the gradation curve (eg poorly graded)Mechanical analysis on four different samples designated as A, B. Cand Dwere carried out in a soil laboratory. The results of tests are given below. Hydrometer analysis was carried out on sample D. The soil is non-plastic. Sample D D. liquid limit w 42, plastic limit = 24. plasticity index = 18 Classify the soils per the Unified Soil Classification System. Samples ASTM Sieve Percentage finer than Designation 63.0 mm 100 93 20.0 mm 64 76 6.3 39 100 65 20 mm 600 212 63 A 20 24 98 59 12 90 54 9. 47 100 34 95 23 69 7. 46 2 31 100 60 20 Sand Coles >762 mm Clay Silt Gravel Fine Course lo medium 0.001 001 0.075 0.1 10 100 Particle size (mm) Samples A,BandC Figure Ex. 3.21 Percentage finer|Laboratory testing was performed on two soil samples (A and B). (a) Determine the USCS classification symbol for Sample A. (b) Determine the AASHTO classification for Sample B. Sieve No. Sieve Opening (mm) A- Percent Passing B - Percent Passing 3 inch 76.2 100 1.5 inch 38.1 98 0.75 inch 19.1 96 4 4.75 77 100 10 2.00 96 20 0.85 55 94 40 0.425 73 100 0.15 30 200 0.075 18 55 Liquid Limit 32 52 Plastic Limit 25 32 A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate the wet density of the CL sample. (b) A small piece of the CL sample had a wet weight of 140.9 grams and a weight of 85.2 grams after drying. Compute the water content. (c) Compute the dry density of the CL sample A Standard Proctor test was performed on a soil with a specific gravity of 2.71. For the water content and wet soil unit weight in the following table: a) Plot the moisture-dry unit weight curve b) Find the maximum dry density and optimum…
- Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil laboratory. The results of tests are given below. Hydrometer analysis was carried out on sample D. The soil is non-plastic. Sample D. liquid limit w 42, plastic limit = 24, plasticity index = 18 Classify the soils per the Unified Soil Classification System. Samples ASTM Sieve Percentage finer than Designation 63.0 mm 100 93 20.0 mm 64 76 6.3 39 100 65 20 mm 600 212 63A 20 24 98 59 12 90 54 5 9. 47 100 34 95 23 69 7. 46 2 31 100 HO 60 20 Sand Course lo medium Cotles l>762 mm Clay Silt Gravel Fine 0.001 001 0.075 0.1 10 100 Particle size (mum) Figure Ex. 3.21 Percentage finerIn a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: There is no clay in the sample the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample 95.5% of the sample is Sand and SiltParagraph Liquid Limit Determination Specimen No. No. of Blows Wt. of Container Wt. of Container + Wet Soil Wt. of Container + Dry Soil İ. ii. a. The following data was obtained from Liquid Limit Test conducted at a Soil Lab. Using thedata given in Table 01, determine the following; Table 01: Liquid Limit Test data for the particular soil sample Unit (g) (g) (g) 1 14 7.13 27.93 T Body Text T Heading 1 T List Para... T No Spac... 21.33 2 20 7.33 27.33 21.23 3 28 7.73 28.43 22.33 F/QAP/021/004 4 32 10.93 Styles 30.13 24.63 5 39 7.23 26.53 21.13 Determine the Liquid Limit and Flow Index If Plastic Limit of this soil is 22. Classify the soil based on BS Soil Classification system. T Norma
- Q5) A: Laboratory test results on the soil (L.L=35% and P.L-21%) is given in the following Table below. Classify the soil by using the unified classification system (10 mark) (showing all steps). Sieve Size(mm) Weight retained (gm) 4.75 2 0.425 0.25 0.075 Pan 135 70 60 30 142.5 462.5 B: A fine-grained soil has a liquid limit of 200% and a plastic limit of 45%, The natural water content of the soil in the field is 60% and the clay content is 63%, Calculate the plasticity index, the liquidity index and the activity. (10 mark)If the weight of sample of sand in sieve analysis test was 420 gm and the weight retained on sieve are shown in table below. Is the sand satisfying the specification? Calculate the fineness modulus of sand and what is the average size ? Sieve size 10 2.36 1.18 0.6 0.3 0.15 < 0.15 (mm) Weight 8.4 63 96.6 143 59 34 16 retained (gm) Sieve size Specification limits for cumulative passing (mm) Zone 1 Zone 2 Zone 3 Zone 4 9.5 100 100 100 100 4.75 100 - 90 100 - 90 100 - 90 100 -95 2.36 95 -60 100 - 75 100 - 85 100 - 95 1.18 70 - 30 90 - 55 100 - 75 100 - 90 0.6 34 15 59 - 35 79 - 60 100 - 80 0.3 20 - 5 30 - 8 40 - 12 50 - 15 0.15 10 - 0 10 - 0 10 - 0 15 - 0 < 0.15 ------ ------The table shows the laboratory result of the sieve analysis of the sample. Determine the percent finer at size 0.74and 0.004. Determine also the soil classification using AASHTO.