Determine the minimum height h of the beam shown in Fig. P-508 if the flexural stress is not to exceed 20 MPa. Figure P-508 5 kN 2 m 2.5 kN/m h + 1m 3 m ח 80 R2
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A: given data;maximum flexural stress (τ)=20ksi=20*103lb/in2
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- A hollow box beam with height h = 16 in,, width h = 8 in,, and constant wall thickness r = 0.75 LiL is shown in the figure. The beam is constructed of steel with yield stress ty = 32 ksi. Determine the yield moment My, plastic moment A/p, and shape factor.Determine the plastic modulus Z and shape factor/for a W 12 x 14 wide-flange beam. Obtain the cross-sectional dimensions and section modulus of the beam from Table F-l(a) in Appendix F.A wood beam reinforced by an aluminumchannel section is shown in the figure. The beam hasa cross section of dimensions 150 mm × 250 mm, andthe channel has a uniform thickness of 6.5 mm. If theallowable stresses in the wood and aluminum are 8MPa and 38 MPa, respectively, and if their moduli ofelasticity are in the ratio 1 to 6, what is the maximumallowable bending moment for the beam?
- In a 2.5 cantilevered I-beam, 2500 kg weight is applied at 0.75 meter from the free end. If the allowable stress in beam is 120 Mpa, determine the section modulus and The base and height of the beam if the base is 75% of its height mm.A simply supported beam is subjected to alinearly varying distributed load q(x) =(x/L)q0 withmaximum intensity q0 at B. The beam has a lengthL = 4 m and rectangular cross section with a widthof 200 mm and height of 300 mm. Determine themaximum permissible value for the maximum intensity,q0, if the allowable normal stresses in tension andcompression are 120 MPa.A small dam of height h= 2.0 m is constructed of vertical wood beamsAB of thickness t=120 mm, as shown in the figure. Consider the beamsto be simply supported at the top and bottom.Determine the maximum bending stress emax in the beams, assuming that the weight density of water is y= 9.81kN/M3
- A beam carries a uniform distributed load of intensity w in N/m. It was determined that Vmax = 7.5w N, (+)Mmax = 5.2w N-m, (-)Mmax = 4.5w N-m. From the given cross section shown, ytop = 64.183 mm, ybot = 135.817 mm, and INA = 25.059 x 10 6 mm4. The allowable stresses are as follows: σfT = 30 MPa, σfC = 60 MPa, and τ = 10 MPa. a. The safe uniform load considering tensile flexural strees is _____N/m b. The safe uniform load considering compressive flexural stress is _____ N/m. c. The moment inertia of the area about the neutral axis is _____ mm^3. d. The safe uniform load considering maximum shear force is _____ N/m e. Based on your analysis, the safe uniform load to recommend is _____ N/m.As shown in the figure below, determine the internal loadings at points D and. Consider the weight of the beamwhich is SN lbs per ft complete solution and drawing. if u can please add some explanation thankyou FN = 49 MN = 101 SN = 94A beam carries a uniform distributed load of intensity w in N/m. It was determined that Vmax = 3.75w N, (++)Mmax = 2.53w N-m, (−−)Mmax = 4.5w N-m. From the given cross section shown, ytop = 100mm, ybot = 150mm, and INA = 72.92 x 10 6 mm4. The allowable stresses are as follows: σfT = 40 MPa, σfC = 70 MPa, and τ = 10 MPa. (a) The safe uniform load considering tensile flexural stress is _____ N/m. (b) The safe uniform load considering compressive flexural stress is _____ N/m. (c) The moment of the area about the neutral axis is _____ mm3. (d) The safe uniform load considering maximum shear force is _____ N/m. (e) Based on your analysis, the safe uniform load to recommend is _____ N/m
- The section modulus for the beam of hollow circular cross section of outer and inner diameters as 70mm and 40 mm respectively, is ______________ mm3. The section modulus (unit is in mm3)= ______________ AnswerConsider the beam section below where fc’ = 30 MPa, Es = 200 GPa, determine the bending stress of the steel section if M=180 KN-m in MPa. Express your final answer in two decimal places.N for Newton, m for meter, mm for millimeter, N/(mm^2) for Stress, mm^2 or m^2 for Area, mm^4 for Moment of inertia and Nm for bending moment. Use brackets if the power is MINUS for Example: 0.00125 N =1.25*10^(-3)N. A simply supported beam AB = 11 m has a hollow rectangular cross-section with 14 cm as width, 29 cm as depth and inner thickness as 1 cm is subjected to a point load of 6 N & 8 N acting at C and D respectively and a uniformly distributed load (UDL) of 8 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 2 m. Solution: i) Reaction force at B = ii) Reaction Force at A = iii) The distance from B at which the shear Force value changes from "-" to "+" = iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I = vi) Maximum bending stress = vii) Bending stress at 1 cm from…