Determine the number of molecules of Cr2Os that form when 1.34 x 10° g of oxygencompletely reacts according to the following equation:4 Cr(s) + 3 0:(g) → 2 Cr.Os(s)STARTING AMOUNTADD FACTORANSWERRESET*( )2152.001.34 x 10° 2.52 x 102536.022 x 102352.004.24 x 10°32.001.68 х 105143.78 x 1025g Cr2Osg Crmol O2g O2molecules Cr2Osmol Cr.O3mol Cr

Given the reaction is 4Cr(s) + 3O2(g) -------> 2 Cr2O3 Weight of oxygen = 1.34*103 g = 1340 g

Answered: Determine the number of molecules of…

Determine the number of molecules of Cr:Os that form when 1.34 x 10° g of oxygen completely reacts according to the following equation:

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter5: Gases

Section: Chapter Questions

Problem 161IP: In the presence of nitric acid, UO2+ undergoes a redox process. It is converted to UO22+ and nitric...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

100%

Determine the number of molecules of Cr2Os that form when 1.34 x 10° g of oxygen
completely reacts according to the following equation:
4 Cr(s) + 3 0:(g) → 2 Cr.Os(s)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
2
152.00
1.34 x 10° 2.52 x 1025
3
6.022 x 1023
52.00
4.24 x 10°
32.00
1.68 х 105
1
4
3.78 x 1025
g Cr2Os
g Cr
mol O2
g O2
molecules Cr2Os
mol Cr.O3
mol Cr

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