Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g)4 NO2G) + O2(g) [N205li (M) Initial Rate (M/s) 4.84 x 10 4 9.67 x 10-4 1.16 x 10-3 0.093 0.186 0.224 = 1.7 x 10-2 M-1/2s-IN2O5/3/2 5.6 x 10-2 M-151N2O5)? 5.2 x 10-3 s-IN205] O Rate = 1.6 x 10-3 M1/2s-1IN2O5]1/2 Rate = 6.0 x 101 M-2s-1IN2O5]3 O Rate O Rate %3D Rate %3D %3D

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Chapter17: Equilibrium
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Determine the rate law and the value of k for the following reaction using the data provided.
2 N205(g) → 4 NO29) + O2lg)
[N205li (M)
Initial Rate (M/s)
0.093
4.84 x 10 4
9.67 x 10-4
1.16 x 10-3
0.186
0.224
O Rate = 1.7 x 10-2 M-1/25-1N,O5]3/2
O Rate = 5.6 x 10-2 M-15N205)?
O Rate = 5.2 x 10-3 s-IN205)
O Rate = 1.6 x 10-3 M1/2s-1IN205]1/2
O Rate = 6.0 x 1o-1 M-2s-1IN,053
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) → 4 NO29) + O2lg) [N205li (M) Initial Rate (M/s) 0.093 4.84 x 10 4 9.67 x 10-4 1.16 x 10-3 0.186 0.224 O Rate = 1.7 x 10-2 M-1/25-1N,O5]3/2 O Rate = 5.6 x 10-2 M-15N205)? O Rate = 5.2 x 10-3 s-IN205) O Rate = 1.6 x 10-3 M1/2s-1IN205]1/2 O Rate = 6.0 x 1o-1 M-2s-1IN,053
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