The reaction described by the equation 03(g)+NO(g)-02(g)+NO2(g)O3(g)+NO(g)¬02(g)+ NO2(g) has, at 310 K, the rate law rate of reaction=k[O3][NO]k=3.0x106 M-1·s-1rate of reaction=k[03][NO]k=3.0x106 M-1's-1 Given that [O3]=4.0×10-4 M[03]=4.0×10-4 M and [NO]=8.0x10-5 M[NO]=8.0×1o-5 M at t=0,t=0, calculate the rate of the reaction at t=0. rate: What is the overall order of this reaction?

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section: Chapter Questions
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Give complete answer what is rate?
The reaction described by the equation
03(g)+NO(g)-02(g)+NO2(g)O3(g)+NO(g)-02(g)+
NO2(g)
has, at 310 K, the rate law
rate of reaction=k[O3][NO]k=3.0×106 M-1's-1rate
of reaction=k[03][NO]k=3.0x106 M-1's-1
Given that [03]=4.0×10-4 M[03]=4.0x10-4 M and
[NO]=8.0x10-5 M[NO]=8.0×10-5 M at t=0,t=0,
calculate the rate of the reaction at t=0.
rate:
What is the overall order of this reaction?
Transcribed Image Text:The reaction described by the equation 03(g)+NO(g)-02(g)+NO2(g)O3(g)+NO(g)-02(g)+ NO2(g) has, at 310 K, the rate law rate of reaction=k[O3][NO]k=3.0×106 M-1's-1rate of reaction=k[03][NO]k=3.0x106 M-1's-1 Given that [03]=4.0×10-4 M[03]=4.0x10-4 M and [NO]=8.0x10-5 M[NO]=8.0×10-5 M at t=0,t=0, calculate the rate of the reaction at t=0. rate: What is the overall order of this reaction?
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