Determine the rate law for the production of nitrosyl fluoride (NO2F) that occurs according to the follow palanced chemical equation: 2 NO2 (g) + F2 (g) → 2 NO2F (g) "he following data were obtained from varying the concentrations of the reactants: [NO2] (M) [F2] (M) Initial Rate (M/s) Run 1 0.00130 0.00479 2.16 x 10-4 Run 2 0.00259 0.00479 4.30 x 104 Run 3 0.00612 0.00123 2.61 x 104 Run 4 0.00612 0.00246 5.22 x 10-4 A) B) C) D) E) Rate = k [NO2] [F2] Rate = k [NO2]²[F2] Rate = k [NO2] Rate = k [NO2]?[F2]0.5 Rate = k [NO2] [F2]0.5

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.42QE
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Determine the rate law for the production of nitrosyl fluoride (NO2F) that occurs according to the following
balanced chemical equation:
2 NO2 (g) + F2 (g) → 2 NO2F (g)
The following data were obtained from varying the concentrations of the reactants:
[NO2] (M)
[F2] (M)
Initial Rate (M/s)
Run 1
0.00130
0.00479
2.16 x 104
Run 2
0.00259
0.00479
4.30 x 10-4
Run 3
0.00612
0.00123
2.61 x 104
Run 4
0.00612
0.00246
5.22 x 104
(A)
(B)
(C)
(D)
(E)
Rate = k [NO2] [F2]
Rate = k [NO2]?[F2]
Rate = k [NO2]
Rate = k [NO2]?[F2]0.5
Rate = k [NO2] [F2]0.5
Transcribed Image Text:Determine the rate law for the production of nitrosyl fluoride (NO2F) that occurs according to the following balanced chemical equation: 2 NO2 (g) + F2 (g) → 2 NO2F (g) The following data were obtained from varying the concentrations of the reactants: [NO2] (M) [F2] (M) Initial Rate (M/s) Run 1 0.00130 0.00479 2.16 x 104 Run 2 0.00259 0.00479 4.30 x 10-4 Run 3 0.00612 0.00123 2.61 x 104 Run 4 0.00612 0.00246 5.22 x 104 (A) (B) (C) (D) (E) Rate = k [NO2] [F2] Rate = k [NO2]?[F2] Rate = k [NO2] Rate = k [NO2]?[F2]0.5 Rate = k [NO2] [F2]0.5
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