Determine the spring constant k4 (N/m) if the extension of the whole system is 1.44 m when a force of 29.86 N is applied. Use k1 = 12.67 N/m, k2 = 11.1 N/m, k3 = 28.39 N/m, and k5 = 33.91 N/m. (Use 2 decimal places for the final answer.) Determine the spring constant k4 (N/m) if the extension of thewhole system is 1.44 m when a force of 29.86 N is applied. Use k1= 12.67 N/m, k2 = 11.1 N/m, k3 = 28.39 N/m, and k5 = 33.91N/m. (Use 2 decimal places for the final answer.)k1k4k2k3k3k5

If spring of spring constant k1 ,k2 ,k3 .........kn are in parallel then their equivalent spring…

Determine the spring constant k4 (N/m) if the extension of the whole system is 1.44 m when a force of 29.86 N is applied. Use k1 = 12.67 N/m, k2 = 11.1 N/m, k3 = 28.39 N/m, and k5 = 33.91 N/m. (Use 2 decimal places for the final answer.) k1 k4 k2 k3 k3 k5

Determine the spring constant k4 (N/m) if the extension of the whole system is 1.44 m when a force of 29.86 N is applied. Use k1 = 12.67 N/m, k2 = 11.1 N/m, k3 = 28.39 N/m, and k5 = 33.91 N/m. (Use 2 decimal places for the final answer.) k1 k4 k2 k3 k3 k5

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter2: Newton's Laws

Section: Chapter Questions

Problem 27P: . A hand exerciser utilizes a coiled spring. A force of 89.0 N is required to compress the spring by...

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Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

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Determine the spring constant k4 (N/m) if the extension of the
whole system is 1.44 m when a force of 29.86 N is applied. Use k1
= 12.67 N/m, k2 = 11.1 N/m, k3 = 28.39 N/m, and k5 = 33.91
N/m. (Use 2 decimal places for the final answer.)
k1
k4
k2
k3
k3
k5

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