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- Draw eugenol as a line structure. The double bonds of the benzene ring are fairly unreactive unless you use special catalysts. But the double bond on the side group is reactive. Draw the mechanism of eugenol reacting with HBr to form the two possible carbocation intermediates. Put your intermediates into square brackets. Label each carbocation as a methyl carbon or 1°, 2°, or 3°. Then circle a more stable carbocation if one is more stable. Can you guess what the final product is?Draw the organic product(s) of the following reaction. You do not have to consider stereochemistry. Include cationic counter-ions, e.g., Na+ in your answer, but draw them in their own sketcher. If no reaction occurs, draw the organic starting material. Separate multiple products using the + sign from the drop-down menu.Assume that 2-chloropropane reacts with CN− in an SN2 reaction. Use the JSME editor () to draw the structure of the substitution product of the reaction. The guide on how to draw your structure can be found here Important Note: When drawing the structures in the JME editor please adhere to the following formats: 1. If the nucleophile is OH−, DO NOT manually add the "H" to the final product 2. If the nucleophile is CN−, be sure to include the appropriate bonding between the C and N in the final product
- Rearrangements can occur during the dehydration of 1° alcohols even though no 1° carbocation is formed—that is, a 1,2-shift occurs as the C— OH2+ bond is broken, forming a more stable 2° or 3° carbocation, as shown in Equation [1]. Using this information, draw a stepwise mechanism for the reaction shown in Equation [2]. We will see another example of this type of rearrangement in Section 16.5C.Draw the structure(s) of the major organic product(s) obtained after workup of the following reaction. Use the wedge/hash bond tools to indicate stereochemistry where it exists. If no reaction occurs, draw the organic starting material. Draw structure(s) of product(s) after aqueous workup. Include counter-ions, e.g., Na+, I-, in your submission, but draw them in their own separate sketcher. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.Show how HC≡CH, CH3CH2Br, and (CH3)2CHCH2CH2Br can be used to prepare CH3CH2C≡CCH2CH2CH(CH3)2. Show all reagents, and use curved arrows to show movement of electron pairs.
- C6H5CO2CH2C6H5 can be synthesized by an SN2 reaction. Draw the structures of the alkyl chloride and nucleophile that will give this compound in highest yield. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include all valence lone pairs in your answer. Separate multiple reactants using the + sign from the drop-down menu. When a metal counterion is needed, use Na+, but draw it in its own sketcher.Alcohols react with sulfonyl chlorides to form sulfonate esters. Only the O-H bond of the alcohol is broken in the reaction, and so no inversion of configuration occurs. The resulting sulfonate esters are reactive in SN1 and SN2 reactions since the sulfonate group is a very weak base and is therefore a good leaving group.Draw curved arrows to show the movement of electrons in this step of the mechanism.In the drawing area below, create an acetal with 1 methoxy group, 1 ethoxy group, and a total of 8 carbon atoms
- Compound X is insoluble in cold KMnO4, Br2 in CCl4, and conc. H2SO4. Compound X is most likely: a. an alkane b. none of these c. an alkene d. an alcohol e. an alkyl halide Indicate which of the ff. statements regarding nucleophilicity is incorrect. F- is more nucleophilic, hence, more reactive towards methyl iodide than Cl-. Second row elements are more nucleophilic than first row elements of comparable basicity. The rate of SN2 reaction may be markedly affected by the nucleophilicity of the attacking atom. Nucleophilicity is the affinity of a nucleophile to an electrophilic carbon Which of the following alkynes can be deprotonated by NaNH2 in liquid NH3? 3-Methylhex-2-yne Pent-2-yne 3-Methylbutyne none of these Hex-3-yneStart with condensed structural formula CH3-CH(OH)-CH(CH3)-CH2-CH(CH3)2 and react it first with H2SO4 and high heat, to produce a major substrate product. Then, take that major substrate product, and use it as the substrate of the next reaction, by reacting it with Br2 (in the presence of CH2Cl2 solvent), to produce the FINAL MAJOR substrate product. The complete correct condensed structural formula for the major substrate product after reaction step 1 is ___________. (If no new product is formed in this step, type "no reaction.") The complete correct condensed structural formula for the final major substrate product (after reaction step 2) is __________ . (If no new product is formed in this step, type "no reaction.")A hydrocarbon of unknown structure has the formula C8H10. On catalytichydrogenation over the Lindlar catalyst, 1 equivalent of H2 is absorbed. Onhydrogenation over a palladium catalyst, 3 equivalents of H2 are absorbed.(a) How rnany degrees of unsaturation are present in the unknown?(b) How many triple bonds are present?(c) How many double bonds are present?(d) How many rings ar e present?(e) Draw a structure that fits the data.