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- The product of reaction between acetone and bromine (excess) with KOH excess is A. Ch2BrCOCh3 B. ChBr3 C.ChBr2COCH3 D.CBr3COCH3 E.Ch2BrCOCHBr21. what is the Nature of the leaving group (LG)? 2. what is the relative size of activation energy (Ea) for each reaction? 3. what is the Hammond's postulate? 4. what are the Relative thermodynamic stability of the reactive intermediates? 5. what is Influence of the solvent (if given) on the reactions and intermediates?Organometallic reagents and alkoxides are strong bases as well as being good nucleophiles. Given the pKa values below, which reagent is the stronger base, nBuLi (CH3CH2CH2CH2LI) or the tert-butoxide anion ((CH3)3CO‒)? Explain your choice clearly in terms of structure andbonding. (Comparing the pKa values is not an explanation.) (CH3)3COH pka= 16.54CH3CH2CH2CH3 pka= 50
- Complete the reaction: 42K19 → + β + [a]_____________Can someone explain the answers to 28, 29, and 30? The answers are B, A, A. I understand lindar catalyst makes cis alkenes and Na/NH3 makes trans alkenes but I dont understand how the second step of Br2, OsO4 influences the stereochemistry between the 2 . Will rate quickly if helpful. Thanks!10.14 Complete the following reactions: Show the step-by-step process. Do not use shortcut methods. Make it as detailed as it can be. Encode (not hand-written)!
- Describe how the product is purified. 4,4'-DIBROMOBIPHENYL [Biphenyl, 4,4'-dibromo-] Submitted by Robert E. Buckles and Norris G. Wheeler1. Checked by R. S. Schreiber, Wm. Bradley Reid, Jr., and Robert W. Jackson. 1. Procedure In a 15-cm. evaporating dish is placed 15.4 g. (0.10 mole) of finely powdered biphenyl (Note 1). The dish is set on a porcelain rack in a 30-cm. desiccator with a 10-cm. evaporating dish under the rack containing 39 g. (12 ml., 0.24 mole) of bromine. The desiccator is closed, but a very small opening is provided for the escape of hydrogen bromide (Note 2). The biphenyl is left in contact with the bromine vapor for 8 hours (or overnight). The orange solid is then removed from the desiccator and allowed to stand in the air under a hood for at least 4 hours (Note 3). At this point, the product weighs about 30 g. and has a melting point in the neighborhood of 152°. The crude 4,4'-dibromobiphenyl is dissolved in 75 ml. of benzene, filtered, and cooled to 15°. The…The molecules below react in a displacement reaction. Determine the products) and assign configuration (R/S) to any stereogenic centers in the product. The Cahn-Ingold - Prelog rules can be used to assign priority to the four different groups on a stereogenic center.Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
- Data: Nitration of methyl benzoate: Weight of filler paper: 0.682g Mp product: 76-77 C Nitration of Acetanilide: Weight of filler paper: 0.691g Weight of filler paper product: 1.232g Mp product: 212-214 C calculate the theoretical yield for the mononitration of (a) acetanilide and (b) methyl benzoateShow the Reaction of ROH with SOCl2 + Pyridine—An SN2 Mechanism ?A solution of pure (S)-2-iodobutane ([a] = +15.90°) in acetone is allowed to react with radioactive iodide, 131I -, until 1.0% of the iodobutane contains radioactive iodine. The specific rotation of this recovered iodobutane is found to be +15.58°. (a) Determine the percentages of (R)- and (S)-2-iodobutane in the product mixture.