In a certain experiment, 3.597 g of Ca3P₂(s) reacts with 8.405 g of H₂O(/). (a) Which is the limiting reactant? (Example: type Ca3P2 for Ca3P₂(s)) is the limiting reactant. (b) How many grams of Ca(OH)₂(s) form? g of Ca(OH)₂(s) form. 1 CajP₂ (s) + 6H₂O() → 3 Ca(OH)₂(s) + 2 PH₂(g) (c) How many grams of PH3(g) form? 9 g of PH3(g) form. (d) How many grams of the excess reactant remains after the limiting reactant is completely consumed? g of excess reactant remain.
In a certain experiment, 3.597 g of Ca3P₂(s) reacts with 8.405 g of H₂O(/). (a) Which is the limiting reactant? (Example: type Ca3P2 for Ca3P₂(s)) is the limiting reactant. (b) How many grams of Ca(OH)₂(s) form? g of Ca(OH)₂(s) form. 1 CajP₂ (s) + 6H₂O() → 3 Ca(OH)₂(s) + 2 PH₂(g) (c) How many grams of PH3(g) form? 9 g of PH3(g) form. (d) How many grams of the excess reactant remains after the limiting reactant is completely consumed? g of excess reactant remain.
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.20QP: Propane, C3H8, is the fuel of choice in a gas barbecue. When burning, the balanced equation is...
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