Draw the structure(s) of the major organic product(s) obtained after workup of the following reaction. 1 eq. HBr CH3 Nicotine tobacco alkaloid
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- How might one use LDA (lithium disopropyl amide) in THF, at -78 degrees, as part of a synthesis of the molecules below? Hi there, can someone please help me solve this problem? Please make sure to clarify all steps taken to go about solving for the products and explain various terms and rules that should be known or correlate with the question. I'm using these questions to study for our final exam and need some extra clarification on rules and steps. Thank you very much in advance!Give five (at least) different synthetic routes (different type reaction to prepare benzoic acid from benzene..give a clear handwritten answer asap..?Show the product formed as a result of the reaction between propanoic acid and benzylalcohol in an acidic environment by writing the reaction mechanism together.
- How different would step 4 be if the amine was secondary? Show curved arrows and explain the mechanism!1) Based on the Material Safety Data Sheets (MSDS) for the compounds, which of the compounds in this experiment is the most hazardous, and why (you have been given a representative aryl halide rather than all of the alkenes – as the products are all new, there’s not a simple answer to gauge their potential hazard)? 2,3-dihydrofuran,2-Mercaptobenzimidazole,Selectfluor, Dimethylformamide,dichloromethane-methylene chloride.Please give me a technique on how to do these. Should I just remove the halide (e.g. Cl) then attach the remaining figure to a benzene? Will that always work? Or do you have any techniques you can suggest? An easy one without much solving?
- When the hypochlorite oxidation is performed on secondary alcohols such as 1-phenolethanol, the product of the reaction is benzoate ion and trichloromethane if an excess of hypochlorite is used in the absence of a buffer to keep the pH below 10. Explain the formation of these products (Hint: what reaction do the products remind you of?) Provide a complete mechanism?Explain why the following reaction is not a good way to prepare 1-phenylpentane: benzene + 1-chloropentane + AlCl3 → 1-phenylpentane In your scratch work, give the full, curved-arrow mechanistic explanation of what would happen, and indicate what would likely be your main product or products.The reaction of 1-bromoheptane with the propionate anion to give heptyl propionate ester is greatly accelerated by adding catalytic amounts of KI. Explain.
- 3) While we expect to get one major product, this reaction could potentially have some issues with formation of multiple products. What is the relationship between the two major products that you might expect for the reaction of E-stilbene and dimethyl fumarate? Why will this not matter when you look at the NMR? 4) In addition to the issue raised in prelab Q3, 2,3-dihydrofuran and styrene will also give give two additional major products – what is their relationship, and will this matter when you look at the NMR?A student was given from the list of the compounds below A, B and D blindly and asked to identify them all. He treated each of them with Brady's reagent (2,4-ditrophenylhydrazine) and isolated a bright yellow compound for one of them, but the other two gave false negatives. The student reasoned that the false negatives may be due to sterics and, on further thinking, it dawned on him that he might be able to rule out one of the false negatives with the haloform test. What compound did he find compatible with the haloform test? That compound did indeed give a false negative in the Brady test. Which of the other two was positive in the Brady test? A = haloform B = Brady A = haloform D = Brady B = haloform A = Brady B = haloform D = Brady D = haloform A = Brady D = haloform B = BradyWrite TRUE if the statement is correct and FALSE if the statement is wrong. Please answer them all Substitution reactions do not occur in aromatic rings because of pi-electron delocalization. The resulting iodinated aspirin has a higher Rf compared to aspirin after visualizing with ferric chloride. The mobile phase used in determining the Rf of the iodinated aspirin is 5% ethyl acetate in acetic acid. When isopropyl alcohol reacts with HCI, the resulting product is 2-chloropropane. In Fehling's test, the theoretical product after an aldehyde is mixed with Fehling's Solution is alcohol. lodoform, which has a molecular formula of CH3l, is indicative that a ketomethyl group is present. Based on the physical property, hydroquinone has a lower boiling point compared to catechol. Picric acid, being a phenolic compound, tests positive for the FeCl3 test. Nucleophilic molecules are electron-rich molecules that can "attack" electron-deficient molecules. When FeCl3 is used in visualizing…