@clean solution 7 The mean effective pressure of an Otto cycle may be expressed asNhAP(a) (r- 1)(y – 1)MthAP(b) (r-1)Y NHAP(c) (r- 1)(Y- 1)Nth (AP)r(d) (r-1)(y-1)Here,is thermal efficiency of cycle, AP is pressure rise during heat transfer, r compressionNthratio and y is ratio of specific heats.

Answered: Image /qna-images/answer/f01a95e2-fce2-4ffd-a3ce-3032c3c853ec.jpg

Answered: D(y – 1) (b) (r-1) thAP D(Y – 1) Nth…

D(y – 1) (b) (r-1) thAP D(Y – 1) Nth (AP)r (d) (r-1)(y-1) is thermal efficiency of cycle, AP is pressure rise during heat transfer, r compression y is ratio of specific heats.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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For the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate: WFS_A * X - WFS_G(X-1) = 1 where WFS_A = mass fraction of NH3 in solution form the absorber WFS_G = mass fraction of NH3 in solution from the generator X-1 =mass of solution from the generator per unit mass of refrigerant flow For large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psi Consider a large NH3/H2O plant operating per the schematic below: Known/given: i. Refrigeration load = 500 tons ii. Evaporator temperature (state point 10) = 41.1 F iii. Evaporator pressure (state point 10) = 75 psia iv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber) v. Strong aqua solution temperature (state point 3) = 105 F vi. Condenser temperature (state point 8) = 100 F vii. Condenser and tower pressure (state point 7) = 211.9 psia viii. Concentration split, WFS_G - WFS_A =6%…