(e) It turns out that compounds of V" are very unstable in the presence of oxygen gas or oxide ions. Reactions like these below can occur sequentially, even at room temperature. Comment on changes in vanadium's oxidation state (if any) in each reaction (oxidized, reduced or no change) 4Vst + 100 → 2V,O5 2V,0; - 4VO, + O, 2VO, + 4H* 2VO2 + 2H,O Trivia: VO* = vanadyl ion with charge of 2+.

Organic Chemistry: A Guided Inquiry
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Author:Andrei Straumanis
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Chapter5: Resonance
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(e) It turns out that compounds of V" are very unstable in the presence of oxygen gas or oxide ions. Reactions
like these below can occur sequentially, even at room temperature. Comment on changes in vanadium's oxidation
state (if any) in each reaction (oxidized, reduced or no change)
4V$+ + 100→ 2V,O5
2V,0, → 4VO, + O,
2VO, + 4H
→2VO2 +2H,O
Trivia: VO2 = vanadyl ion with charge of 2+.
(f) Are conditions right for that last reaction of part (e) to occur in our container? Why or why not?
Transcribed Image Text:(e) It turns out that compounds of V" are very unstable in the presence of oxygen gas or oxide ions. Reactions like these below can occur sequentially, even at room temperature. Comment on changes in vanadium's oxidation state (if any) in each reaction (oxidized, reduced or no change) 4V$+ + 100→ 2V,O5 2V,0, → 4VO, + O, 2VO, + 4H →2VO2 +2H,O Trivia: VO2 = vanadyl ion with charge of 2+. (f) Are conditions right for that last reaction of part (e) to occur in our container? Why or why not?
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