m1 Viim₂8v2fx4. A proton is accelerated in a particle accelerator andcollides elastically with a stationary proton in a cooledhydrogen target.1.672 x 10-27 kgm₁ = m₂ =V₁i = 8.2 x 105 m/s0₁ = 30° 0₂ 60°V₂i = 0 m/sa.) Write out the conservation equations for this collisiongeometry.b.) Solve for the velocities of the two protons after thecollision:and v₂f.V₁fc.) Compute the velocity of the center of mass.

E m1 Vii m₂ 8₁ v2f 4. A proton is accelerated in a particle accelerator and collides elastically with a stationary proton in a cooled hydrogen target. m₁ = m₂ = 1.672 x 10-27 V₁i = 8.2 x 105 m/s 0₁ = 30° 0₂ = 60° kg V₂i = 0 m/s a.) Write out the conservation equations for this collision geometry. b.) Solve for the velocities of the two protons after the collision: v₁f and v₂f. c.) Compute the velocity of the center of mass.

E m1 Vii m₂ 8₁ v2f 4. A proton is accelerated in a particle accelerator and collides elastically with a stationary proton in a cooled hydrogen target. m₁ = m₂ = 1.672 x 10-27 V₁i = 8.2 x 105 m/s 0₁ = 30° 0₂ = 60° kg V₂i = 0 m/s a.) Write out the conservation equations for this collision geometry. b.) Solve for the velocities of the two protons after the collision: v₁f and v₂f. c.) Compute the velocity of the center of mass.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter11: Collisions

Section: Chapter Questions

Problem 45PQ

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