e the information in the pK table below to determine which side of the equilibrium is favored for each of the reactions in e second table. acid CH4 SH CH₂OH, SH, OH SH OH + pKa O 50 19 CHÍNH, + 10.5 9 -2.2 -6.8 + + CHA acid CHÍNH, CHÍNH, OH L i OH Ï OH SH OH OH OH pKa 36 10.6 Equilibrium Equation 10.0 4.8 -6.1 -7.2 CH,NH, + OH + O i + + H₂-C SH₂ Left Favored O O O O Equal O O O O C. 0 olo Ar Righ Favor O O O O
e the information in the pK table below to determine which side of the equilibrium is favored for each of the reactions in e second table. acid CH4 SH CH₂OH, SH, OH SH OH + pKa O 50 19 CHÍNH, + 10.5 9 -2.2 -6.8 + + CHA acid CHÍNH, CHÍNH, OH L i OH Ï OH SH OH OH OH pKa 36 10.6 Equilibrium Equation 10.0 4.8 -6.1 -7.2 CH,NH, + OH + O i + + H₂-C SH₂ Left Favored O O O O Equal O O O O C. 0 olo Ar Righ Favor O O O O
Chapter30: Orbitals And Organic Chemistry: Pericyclic Reactions
Section30.SE: Something Extra
Problem 41AP: In light of your answer to Problem 30-40, explain why a mixture of products occurs in the following...
Related questions
Question
Transcribed Image Text:e the information in the pK₁ table below to determine which side of the equilibrium is favored for each of the reactions in
e second table.
acid
pK₁
pKa
CH4
SH
u
CH₂OH₂
+
SH₂
+
OH
L
SH
OH
+
50
19
10.5
+
CH₂NH3 +
9
-2.2
м
- 6.8
+ CH4
acid
CH,NH,
CH₂NH3
OH
Ï
OH
+
OH
Ï
SH
OH
OH
OH
36
10.6
10.0
Equilibrium Equation
4.8
-6.1
- 7.2
CH,NH, +
OH
SH₂
ii
+
+
i
SH₂
0
+ H₂-C
O
Left
Favored
Equal
O
O
olo
Ar
Right
Favored
O
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 6 steps with 6 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you