En la titulación de 25.00 mL del ácido diprótico ácido butírico (Illamémosle H2B) 0.100 M con KOH 0.100M el pH entre el primer punto de equivalencia y el segundo punto de equivalencia sería Select one: O a. pH = 2(pKa1+pKa2) O b. pH=pKa2 + log [B-²]/[ HB] C. pH=pK a2 + log [H2B]/[ B2] O d. pH=pK a1 + log [HB-]/[H2B]

En la titulación de 25.00 mL del ácido diprótico ácido butírico (Illamémosle H2B) 0.100 M con KOH 0.100M el pH entre el primer punto de equivalencia y el segundo punto de equivalencia sería Select one: O a. pH = 2(pKa1+pKa2) O b. pH=pKa2 + log [B-²]/[ HB] C. pH=pK a2 + log [H2B]/[ B2] O d. pH=pK a1 + log [HB-]/[H2B]

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter20: Carboxylic Acids And Nitriles

Section20.3: Biological Acids And The Henderson–hasselbalch Equation

Problem 5P: Calculate the percentages of dissociated and undissociated forms present in the following solutions:...

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