Enter the values for the array: After sorting: 4 8 9. 3 2 3 ∞ -oo 54
Write a C++
Can u please continue this code. I really need help about this.
//header files
#include <iostream>
using namespace std;
int main()
{
int x[100],evenX[100],oddX[100],even=0,odd=0,i,temp,j ;
cout<<"Enter the 100 values for integer array :"; //prompt the user
for(i=0;i<100;i++)
{
cin>>x[i]; //input from the user
}
for(int i=0;i<100;i++)
if(x[i]%2==0) //chech whether value is even or odd
{
evenX[even]=x[i]; //if value is even,store the value in array
even++;
}
else
{
oddX[odd]=x[i]; //if value is odd,store the value in array
odd++;
}
//sort the even elements of the array
for(i=0;i<=even;i++)
{
for(j=i+1;j<even;j++)
{
if(evenX[i]>evenX[j])
{
temp =evenX[i];
evenX[i]=evenX[j];
evenX[j]=temp;
*The values after sorting should be in a vertical manner for the outcome of the program;
Trending now
This is a popular solution!
Step by step
Solved in 6 steps with 4 images