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Example 5.5 A component machined from a plate made of steel 45C8 (S, = 630 N/mm') is shown in Fig. 5.29. It is subjected to a completely reversed axial force of 50 kN. The expected reliability is 90% and the factor of safety is 2. The size factor is 0.85. Determine the plate thickness i for infinite life, if the notch sensitivity factor is 0.8. 5r P= 1 50 kN 100 P=1 50 kN 50 Fig. 5.29

Example 5.5 A component machined from a plate made of steel 45C8 (S, = 630 N/mm') is shown in Fig. 5.29. It is subjected to a completely reversed axial force of 50 kN. The expected reliability is 90% and the factor of safety is 2. The size factor is 0.85. Determine the plate thickness i for infinite life, if the notch sensitivity factor is 0.8. 5r P= 1 50 kN 100 P=1 50 kN 50 Fig. 5.29

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Section: Chapter Questions
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A component machined from a plate made of steel 45C8 (Sut = 630 N/mm2) is shown in figure below. It is subjected to a completely reversed axial force of 50 kN. The expected reliability is 90% and the factor of safety is 2. The size factor is 0.85.Determine the plate thickness t for infinite life, if the notch sensitivity factor is 0.8.

Example 5.5 A component machined from a plate made of steel 45C8 (S, = 630 N/mm) is shown in Fig. 5.29. It is subjected to a completehy reversed axial force of 50 kN. The expected reliability is 90% and the factor of safety is 2. The size factor is 0.85. Determine the plate thickness t for infinite life, if the notch sensitivity factor is 0.8. 5r P= + 50 kN 100 P= + 50 kN 50 Fig. 5.29
Transcribed Image Text:Example 5.5 A component machined from a plate made of steel 45C8 (S, = 630 N/mm) is shown in Fig. 5.29. It is subjected to a completehy reversed axial force of 50 kN. The expected reliability is 90% and the factor of safety is 2. The size factor is 0.85. Determine the plate thickness t for infinite life, if the notch sensitivity factor is 0.8. 5r P= + 50 kN 100 P= + 50 kN 50 Fig. 5.29
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