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- Ff.192. With explanation please ...Confused with pchem. I don't know how to find v initialChoices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
- Determine the average rate of change of BB from ?=0 st=0 s to ?=272 s.t=272 s. A⟶2BA⟶2B Time (s) Concentration of A (M) 0 0.7300.730 136136 0.4450.445 272272 0.1600.160 rateB= __________M/s( dint answer afrr 10.10 asapAssume no acid-base catalysis occurs and the following data: Under biological conditions (310 K) 1. dGb = -20.00 kJ/mol. 2. The dG of E +S binding to ES (dGs) is -3.00 kJ/mol. 3. dGd mismatch of energy in ES = +2.00 kJ/mol. What is the catalytic power (kcat/k_uncat) at 360 K? Use 1 decimal place.
- The Lineweaver-Burke equation of a reaction is 1/v = 0.3 (1/s) + 0.2.Question: What's the Vmax of the reaction?Which one of the following statement is not true regarding the material balance equation: AR = IR – OR + GR Group of answer choices OR is the Output Rate, it represents the amount of mass leaving the process boundary AR is the Accumulation Rate, it’s 0 under steady-state conditions IR is the Input Rate, and its unit should be mass per time GR is the Generation Rate and it can only be positive, as indicated by the plus signUsing the kinetic data pictured, estimate Vmax and Km for the catalysis of Substrate 1 by the following enzyme (using the correct units).
- In a batch reactor, reactant A is steadily converted into product B. The initialconcentration of reactant A is 100 mg/L. During a 10-hour reaction course, it wasobserved that the concentration of A in the reactor decreased at a constant rate of 10mg/L per hour. Based on the result, you can determine that the transformation reactionA→B follows ( ) with respect to reactant A.What type of catalytic mechanism (heterogenous or homogenous) exist in Fresco painting? Why?Ethylene (CH2CH2) is the starting point for a wide array of industrial chemical syntheses. For example, worldwide about 8.0x10^10 kg of polyethylene are made from ethylene each year, for use in everything from household plumbing to artificial joints. Natural sources of ethylene are entirely inadequate to meet world demand, so ethane (CH3CH3) from natural gas is "cracked" in refineries at high temperature in a kinetically complex reaction that produces ethylene gas and hydrogen gas. Suppose an engineer studying ethane cracking fills a 75.0 L reaction tank with 23.0 atm of ethane gas and raises the temperature to 750.°C. He believes Kp=6.0 at this temperature. Calculate the percent by mass of ethylene the engineer expects to find in the equilibrium gas mixture. Round your answer to 2 significant digits.