In an experiment an analyst has observed thatSSxy equals-212.35, SSx equals 237.16 and SSy-858.49. The sample average for x was 193.1and the sample average for y was 15.2.Assumethat a linear regression model is appropriate.These results imply that, if X equals 200, theexpected value for Y would be09.02O 37,618.95O 26,824.83O 12.5

Compute the y value if x = 200 SSXY ∑x-x¯y-y¯ -212.35 SSX ∑x-x¯2 237.16 SSY ∑y-y¯2 858.49…

Answered: experiment an analyst has observed that…

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter4: Linear Functions

Section4.3: Fitting Linear Models To Data

Problem 34SE: For the following exercises, consider this scenario: The profit of a company decreased steadily...

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Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?
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experiment an analyst has observed that equals-212.35, SSx equals 237.16 and SS B49. The sample average for x was 193.1 he sample average for y was 15.2.Assume linear regression model is appropriate.