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- a) Sighting down the C3-C4 bond, draw the gauche (60 degrees) and anti (180 degrees) Newman projections of 2,4-dimethylhexane. b) Circle the conformation that you drew that is lower energy.1. Estimate the relative stabilities of the 4 conformationseclipsed and eclipsed n-pentane by drawing the corresponding Newman projections in descending order according to their stability. Place the most stable or lowest energy on the left. 2. Explain what the difference in energy between the most stable and the least stable is due to. 3. What is the difference in stability between the two staggered conformations?For pentane draw Newman projections for the Syn-periplanar, conformation. the Anti- periplanar conformation and a Gauche conformation. Use C2 as the front carbon and C3 as the back carbon. Label each conformation, circle the highest energy conformation andunderline the lowest energy conformation.
- Build a model of methylcyclohexane, and use the model to complete the following Newmanprojections of methylcyclohexane in the chair conformation: a. When the methyl group is in an axial or equatorial (circle one) position, the molecule is inits lowest potential energy conformation. b. Label one Newman projection above anti and the other gauche to describe the relationshipbetween the methyl group and C3 of the ring. c. In general, which is a lower PE conformation, anti or gauche? d. Explain how your answer to b and c provide an explanation for why it is more favorable fora large group to be in an equatorial than an axial position.For rotation about the C3-C4 bond of 2-chlorohexane: a) Draw a Newman projection showing the most stable conformation. b) Draw a Newman projection showing the least stable conformation.Pls do fast within 5 minutes and i will give like for sure Solution must be in typed form 1. The alcohol group is axial or equatorial. 2. The methyl group is axial or equatorial. 3. The substituents are trans or cis. 4. The given chair conformation is higher/equal/lower in energy than the flipped conformation (not provided). 5. When drawing a planar form of the cyclohexane given, the methyl group would be wedged or dashed.
- Consider 1-bromopropane, CH3CH2CH2Br. (a) Draw a Newman projection for the conformation in which CH3 and -Br are anti (dihedral angle 180°). (b) Draw Newman projections for the conformations in which - CH3 and -Br are gauche (dihedral angles 60° and 300°). (c) Which of these is the lowest energy conformation? (d) Which of these conformations, if any, are related by reflection?Using Newman projections, draw each of the following molecules it most stable staggered, least stable staggered, least stable eclipse and most stable eclipse conformations with respect to the bond indicated: (b) 4-isoproply-2,4,5-trimethylheptane, C4-C5(c) 6-isopropyl-2,5-dimethylnonane, C5-C6 please answer B and CSight along the C2-C1 bond of 2-methylpropane (isobutane).(a) Draw a Newman projection of the most stable conformation.(b) Draw a Newman projection of the least stable conformation.(c) Make a graph of energy versus angle of rotation around the C2-C1 bond.(d) Assign relative values to the maxima and minima in your graph, given that an H↔H eclipsing interaction costs 4.0 kJ/mol and an H↔CH3 eclipsing interaction costs 6.0 kJ/mol.
- Draw a qualatative potential energy diagram for rotation about the C3-C4 bond in 2-methylpentane. Show newman projections for all conformations located at the maximum and minimum points on the diagram.Draw a Newman projection, similar to Figure 3-25, down the C1¬C6 bond in the equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5.Rank the following groups in order of decreasing priority. −H, −CH3, −Cl, −CH2Cl