Fermt TL gaGSkin ja-0,630/a) vo My le.ly - ly It 2 + cor28 + tin20, , tan20,- sin20+ Teo20, nsn 2 mak A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T= 500 Nm ve G = 77,2 GPa () O5.34 3.89 4,87 7.86 O8.72

Fermt TL gaGSkin ja-0,630/a) vo My le.ly - ly It 2 + cor28 + tin20, , tan20,- sin20+ Teo20, nsn 2 mak A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T= 500 Nm ve G = 77,2 GPa () O5.34 3.89 4,87 7.86 O8.72

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...

See similar textbooks

Similar questions

Hiii! Plsss help me with this problem. Pls show complete solution and identify the answers from a to e. Arigato! ❤️
Answers (a) er=15.30-250.2/r^2 , etheta=15.30+250.2/r^2 (b) delta c = 8.12x10^-4 in
Suppose we got the following data during a test of a 2- stroke engine in which gas is usedas a fuel:Diameter of the piston = 149 mmStroke length = 179 mmClearance volume = 0.88 literrpm of the engine = 302Indicated mean effective pressure = 6.0 barGas consumption = 6.0 m3/hCalorific value of the gas (fuel) = 16990 kJ/m3Make a clear sketch the geometry of this engine using the data and determine thefollowing:i. Indicated power developed by the engine in watt.ii. Air Standard Efficiencyiii. Indicated thermal efficiency of the engine.
Suppose you're converting a bill of materials for machining feedstock from the British gravitational (U.S. system) of units to International System (SI) units. Your goal is to have all of the material quantities in kilograms. Your bill of materials lists values for required weights of brass rod in pounds. To convert to these values to kilograms you first you divide by gravitational acceleration in feet per second squared to get a mass in slugs, then convert slugs to kilograms using standard conversion factors. Group of answer choices True False
PLEASE ANSWER THEM ALL FOR AN UPVOTE. THANK YOU. Given: Pi constant to be used: 3.14159 Capillary tube: radius = 0.02 cm; length = 9 cm; pressure = 0.7 mmHg Liquid sample: density = 4 ml; time of flow = 4.5 seconds Ans. the ff questions. •What is the pressure in MKS unit? •What is the pressure in CGS unit? •What is the viscosity of the liquid? • If the weight was given as 8.5 grams, what will be the density of the liquid? •What is the kinematic viscosity of the liquid? •What is the fluidity of the liquid?
Pi constant to be used: 3.14159 Capillary tube: radius = 0.02 cm; length = 9 cm; pressure = 0.7 mmHg Liquid sample: density = 4 ml; time of flow = 4.5 seconds Determine (a) pressure in MKS unit, (b) pressure in CGS unit, (c) the viscosity of the liquid, (d) If the weight was given as 8.5 grams, what will be the density of the liquid? (e) the kinematic viscosity of the liquid? (f) and the fluidity of the liquid?
1) An electric motor’s torque is a function of the speed at which it rotates. Many brushed AC motors have a linear toque curve as shown below. If the power output of the motor is equal to the torque (T) multiplied by the rotational speed in rad/s (w), what is the maximum power you can get out of the motor if the stall torque (Tstall) is 0.001 Nm and the no load speed (wno load) of 10,500 RPM? Give answer in Watts.
Electric drives have a wide range of applications in various industries. One common application is in the manufacturing industry, where electric drives are used to control the speed and torque of electric motors that drive various machines and equipment. For example, electric drives are used in conveyor systems, pumps, fans, compressors, and machine tools to regulate the motion and force required for different manufacturing processes. 1. Create simple Process Flow Diagram (PFD) of electric motor used in pumps.
AKN =11 BKN=5 CKN=4 D°=36 E°=50
The horizontal force due to water acting on the bolt (Fh): Fh=ρ×A1×V1×V1--V2 Fh=1000×π4×0.0752×1.254×1.254+11.286( Fh)=69.472 This is the only part I did not understand how to get. Can you please explain more? I arrived with this equation, -P1A1 - P2A2 (cancelled since atmos. Pres.) +Fh = rho A1v1 (v2-v1) Why did P1A1 disappear in your solution? How did you come up with (v1 - - v2) ? What is the control volume? Why did you not do a summation of forces is equal to change in momentum but instead go immediately to getting the horizontal force acting on the bolt?
Hello im reviewing my notes and im confused as to how s and n were able to come up with the equation. Please help. n=(cos30,sin30,0) s=(-cos60,sin60,0) Please explain,thank you
I am unsure of how the equation got to the final result. Can you elaborate on the steps between the last four arrows of this problum?