Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage AVout from a source voltage E. Determine the required value of Rg if E = 5.00 V, AVout = 1.50 V, and R = 1.00 x 10 0. (Hint: Use Kirchhoff's loop rule, substi- tuting AVout = IR2, to find the current. Then solve Ohm's law for R2.) R1 R AV out Figure P18.26

Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage AVout from a source voltage E. Determine the required value of Rg if E = 5.00 V, AVout = 1.50 V, and R = 1.00 x 10 0. (Hint: Use Kirchhoff's loop rule, substi- tuting AVout = IR2, to find the current. Then solve Ohm's law for R2.) R1 R AV out Figure P18.26

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter18: Direct-Current Circuits

Section: Chapter Questions

Problem 26P: Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage Vout from a source...

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Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage Vout from a source voltage . Determine the required value of R2 if = 5.00 V, Vout = 1.50 V and R1 = 1.00 103 (Hint: Use Kirchhoff's loop rule, substituting Vout = IR2, to find the current. Then solve Ohms law for R2. Figure P18.26
Figure P18.19 shows a Wheatstone bridge, a circuit used to precisely measure an unknown resistance R by varying Rvar until the ammeter reads zero current and the bridge is said to be balanced. If the bridge is balanced with Rvar = 9.00 , find (a) the value of the unknown resistance Rand (b) the current in the 1.00 resistor. (Hint: With the bridge balanced, the wire through the ammeter can effectively be removed from the circuit, leaving two pairs of resistors in parallel.) Figure Pl8.19
Figure P18.19 shows a Wheatstone bridge, a circuit used to precisely measure an unknown resistance R by varying Rvar until the ammeter reads zero current and the bridge is said to be balanced. If the bridge is balanced with Rvar = 9.00 , find (a) the value of the unknown resistance Rand (b) the current in the 1.00 resistor. (Hint: With the bridge balanced, the wire through the ammeter can effectively be removed from the circuit, leaving two pairs of resistors in parallel.) Figure Pl8.19
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