Question
Asked Oct 29, 2019
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Find the change in internal energy for this reaction (in kJ)

3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)

(-133.5 kJ= ΔHorxn)

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Expert Answer

Step 1

Given,

enthalpy of the reaction as -133.5kJ.

The change in...

3NO2 (g)+H20
2HNO, (aq) +NO (g)
An=moles of products(g)-moles of reactants (g)
-1-3
=-2
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3NO2 (g)+H20 2HNO, (aq) +NO (g) An=moles of products(g)-moles of reactants (g) -1-3 =-2

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Carboxylic Acids

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