Find the equation for the voltage across the inductor with time. A. vL(t) = (125 V) cos(9580 rad/s)t + # rad) B. vL(t) = (112 V) cos((9580 rad/s){] C. vL(t) = (125 V) cos[(9580 rad/s)t + 1/2 rad] The current in the circuit is given by i(t) = I cos[(9580 rad/s)(), where I is the amplitude current. The voltage amplitude of the AC source is 112 V. D. vL(t) = (112 V) cos[(9580 rad/s)t + 1.03 rad) E. vL(t) = (125 V) cos[(9580 rad/s)t – 1/2 rad) R= 335 2 C = 0.625 µF %3D L = 75.8 mH u

Find the equation for the voltage across the inductor with time. A. vL(t) = (125 V) cos(9580 rad/s)t + # rad) B. vL(t) = (112 V) cos((9580 rad/s){] C. vL(t) = (125 V) cos[(9580 rad/s)t + 1/2 rad] The current in the circuit is given by i(t) = I cos[(9580 rad/s)(), where I is the amplitude current. The voltage amplitude of the AC source is 112 V. D. vL(t) = (112 V) cos[(9580 rad/s)t + 1.03 rad) E. vL(t) = (125 V) cos[(9580 rad/s)t – 1/2 rad) R= 335 2 C = 0.625 µF %3D L = 75.8 mH u

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter14: Inductance

Section: Chapter Questions

Problem 42P: The current I(t) through a 5.0-mH inductor varies with time, as shown below. The resistance of the...

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