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Find the individual contributions of each of the 8 A and 16 V sources to the phasor voltage Vo. V o078 jX1 1620° V 27 Determine V(8 A), the contribution of the 8 A source to Vo. Give your answer in polar form as V.(8 A) =rZ6°, where r20 and -180° <6< 180°. Determine V.(16 V), the contribution of the 16 V source to Va. Give your answer in polar form as V.(16 V) = r20°, where r 2 0 and -180° <0 180°. 28

Find the individual contributions of each of the 8 A and 16 V sources to the phasor voltage Vo. V o078 jX1 1620° V 27 Determine V(8 A), the contribution of the 8 A source to Vo. Give your answer in polar form as V.(8 A) =rZ6°, where r20 and -180° <6< 180°. Determine V.(16 V), the contribution of the 16 V source to Va. Give your answer in polar form as V.(16 V) = r20°, where r 2 0 and -180° <0 180°. 28

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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R=1000 ohm

X1=300 ohm

X2= 100ohm

Given: R, X1, X2. Find the individual contributions of each of the 8 A and 16 V sources to the phasor voltage V. 820° A ーJX。 jX1 + ) 1620° V Determine V.(8 A), the contribution of the 8 A source to Vo. Give your answer in polar form as Vo(8 A) =r28°, where r20 and -180° <6 < 180°. 27 Determine Vo(16 V), the contribution of the 16 V source to V.. Give your answer in polar form as V.(16 V) = r28°, where r 2 0 and -180° <0< 180°. 28
Transcribed Image Text:Given: R, X1, X2. Find the individual contributions of each of the 8 A and 16 V sources to the phasor voltage V. 820° A ーJX。 jX1 + ) 1620° V Determine V.(8 A), the contribution of the 8 A source to Vo. Give your answer in polar form as Vo(8 A) =r28°, where r20 and -180° <6 < 180°. 27 Determine Vo(16 V), the contribution of the 16 V source to V.. Give your answer in polar form as V.(16 V) = r28°, where r 2 0 and -180° <0< 180°. 28
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