fo. A Radon level of more than 4 pCL is considered unsafe for humans. A house-inspector tests following nulland alternative hypothesis.H:us40H:p>40. Describe the type I and Type 2 errors in this experiment.Type I error:Type II Error:Page S of 5

Given: the null and alternate hypotheses are H0: μ≤4.0Ha: μ>4.0

Answered: fo. A Radon level of more than 4 pCL is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a comparison of two methods for the determination of chromium in rye grass, the following results were obtained: Method A, mean(mg/kg Cr)=1.48 Standard deviation(mg/kg Cr)=0.28 n= 6 Method B, mean (mg/kg Cr)=2.33 Standard deviation(mg/kg Cr)=0.31 n=10 Is the precision of these two methods significantly different? Do these two methods give results with means which differ significantly? a=0.05
A z-score of –1.6 has a corresponding Stanine score of:
The NAEP considers that a national average of 283 is an acceptable performance. Using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2019 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2019 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?
Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800.Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.
Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.
A researcher reports an F-ratio with dfbetween = 2 and dfwithin = 30 for an independent-measures ANOVA. a. How many treatment conditions were compared in the experiment? b. How many subjects participated ion the experiment?

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fo. A Radon level of more than 4 pCL is considered unsafe for humans. A house-inspector tests following null and alternative hypothesis. H:us40 H:p>40 . Describe the type I and Type 2 erors in this esperiment. Type I error: Type II Eror: