For a balance three phase circuit, two wattmeter are connected to measure the input power. The reading of two wattmeter is 2000 W and 535.98 W respectively. Determine the power factor of the circuit. (а) 1 (c) 0.34 (b) 0.7 (d) 0.051
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- Two wattmeter’s are connected to measure the input power of a balanced three phase load by two wattmeter method. If the wattmeter readings are W1 = 9800 W and W2= 3300 W and the reverse switch being operated on the meter indicating 3300 W, then the load power factor is given by,......... Complete the answerA three-phase generator provides 3.6 kVA with a 0.85 (delayed) power factor. If first released 2,500 W to the load and as line losses before 80 W per phase, what are the losses in the generator (insert response in W)?In 3 phase 11kVV generator having unity power factor of 100MW load and the sending and receiving end voltage is 11KV and the value of the impedance is j0.242. What isthe value of the reactive power delivered by the capacitor.
- Two wattmeter’s are connected to measure the input power of a balanced three phase load by two wattmeter method. If the wattmeter readings are W1 = 9200 W and W2= 3700 W and the reverse switch being operated on the meter indicating 3700 W, then the load power factor is given by,two wattmeters are connected to measure the input power to a balanced 3-phase load by two wattmeter method, If the total power input is 12kW, and the load power factor is 0.866(lag) determine the instrument readings.I Two wattmeters are connected to measure the input power to a balanced three-phase load. If the wattmeter readings are 9.3 kW and 5.4 kW determine (a) the total output power, and (b) the load power factor
- A TWO-WATTMETER method is used to measure the total real power of the load in Problem , where wattmeter W1 is connected in line A and W2 is connected in line C. Line B being the common tapping point of the voltage coils of W1 and W2. Determine thefollowing:a. Reading of wattmeter W1b. Reading of wattmeter W2c. If a third wattmeter W3 is connected to line B and the two ends of the voltage coils areconnected to lines C and A, what is its reading?d. If the result in Part C is multiplied by 1.732 or square root of 3, what does this valuerepresents?1. Solve the following problem: A THREE-PHASE CIRCUIT WHERE THE BALANCED DELTA LOAD OF 36 + J54 OHMS IS SUPPLIED BY 8,602 OHMS IMPEDANCE CONDUCTORS WITH A PHASE ANGLE OF 54,462 DEGREES. IF THE GENERATOR VOLTAGE IN PHASE B IS 100 VOLTS ANGLE - 120 DEGREES. CALCULATE: A) THE VOLTAGE BC IN LOAD. B) THE POWERS IN THE CONDUCTORS. C) THE POWER TRIANGLE IN THE LOAD.Two-watt meters are connected to measure the input power to a balanced 3-phase load by the two-wattmeter method. If the instrument readings are 8 kW and 4 kW, determine the total power input and the load power factor.
- 1.) A three phase, 3 wire CBA system, with the line voltage Vab =300cis0°,has the following line currents: Ia= 60cis120°, Ib= 62cis-45°,Ic= 15.5cis220° Find the readings of wattmeters in lines a.) A and B b.) B and C C.) A and CDesign a three-phase system such that the phase current in the generator, lines and charging phase is the same. The phase voltage in the generator must be 1000 [V] with ACB sequence. The connected load must be such that the phase current in each load is 10 [A] and its power factor is 0.97 “lagging”.Consider a 3-phase star-delta configuration with a generator and a 3-phase load.The generator supplies voltage of grid-standard 380/220V@50Hz. Each load is (15+15j) Ω.(with standard grid voltages)Measure and fill the table below ( miss out the non measurable ones.).