For the reaction2C2H6(g) + 7O2(g)4CO2(g) + 6H2O(g)H° = -2.86×103 kJ and S° = 92.7 J/KAt standard conditions, this reaction would be product favored at relatively low temperatures. at all temperatures. at relatively high temperatures. at no temperature.
For the reaction2C2H6(g) + 7O2(g)4CO2(g) + 6H2O(g)H° = -2.86×103 kJ and S° = 92.7 J/KAt standard conditions, this reaction would be product favored at relatively low temperatures. at all temperatures. at relatively high temperatures. at no temperature.
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter3: The Second And Third Laws Of Thermodynamics
Section: Chapter Questions
Problem 3.8E: Explain why the high-temperature reservoir of a heat engine must, indeed, be higher in temperature...
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Question
For the reaction
2C2H6(g) + 7O2(g)4CO2(g) + 6H2O(g)
H° = -2.86×103 kJ and S° = 92.7 J/K
At standard conditions, this reaction would be product favored
2C2H6(g) + 7O2(g)4CO2(g) + 6H2O(g)
H° = -2.86×103 kJ and S° = 92.7 J/K
At standard conditions, this reaction would be product favored
at relatively low temperatures.
at all temperatures.
at relatively high temperatures.
at no temperature.
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