For the reaction: C4H10 (g) + 13/2 O₂ (g) → 4 CO2 (g) + 5 H₂O (g) (a) Find an expression of AG (J/mol) as a function of temperature. (b) Find an expression of AH (J/mol) as a function of temperature. (c) Calculate the maximum non-expansion work (J) produced if 500 g of butane is burned at 200°C using the AG model in Part (a)

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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.97QP: When 1.000 g of gaseous butane, C4H10, is burned at 25C and 1.00 atm pressure, H2O(l) and CO2(g) are...
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For the reaction: C4H10 (g) + 13/2 O₂ (g) → 4 CO2(g) + 5 H₂O(g)
(a) Find an expression of AG (J/mol) as a function of temperature.
(b) Find an expression of AH (J/mol) as a function of temperature.
(c) Calculate the maximum non-expansion work (J) produced if 500 g of butane is burned at 200°C
using the AG model in Part (a)
(d) For the combustion of 25 L of butane at 200°C and 1 atm, what amount of heat (J) is evolved at
constant pressure? Use the AH expression model in Part (b)
(e) Deduce an expression of AS (J/mol K) as a function of T.
Molar Heat Capacities
(Use R = 8.314 J/mol-¹ K-¹)
Cp,m
C4H10 = 1.935 + 36.915 × 10-³T – 11.402 × 10-67²
R
Cp,m
0₂:= 3.639 +0.506 × 10-³T — 0.227×105
R
T²
CO₂:
H₂O
Cp,m
R
=
= 5.457 + 1.045 x× 10-³-1.157×105
Cp,m
= 3.470+ 1.450 × 10−³T +
R
T²
0.121x105
T²
Transcribed Image Text:For the reaction: C4H10 (g) + 13/2 O₂ (g) → 4 CO2(g) + 5 H₂O(g) (a) Find an expression of AG (J/mol) as a function of temperature. (b) Find an expression of AH (J/mol) as a function of temperature. (c) Calculate the maximum non-expansion work (J) produced if 500 g of butane is burned at 200°C using the AG model in Part (a) (d) For the combustion of 25 L of butane at 200°C and 1 atm, what amount of heat (J) is evolved at constant pressure? Use the AH expression model in Part (b) (e) Deduce an expression of AS (J/mol K) as a function of T. Molar Heat Capacities (Use R = 8.314 J/mol-¹ K-¹) Cp,m C4H10 = 1.935 + 36.915 × 10-³T – 11.402 × 10-67² R Cp,m 0₂:= 3.639 +0.506 × 10-³T — 0.227×105 R T² CO₂: H₂O Cp,m R = = 5.457 + 1.045 x× 10-³-1.157×105 Cp,m = 3.470+ 1.450 × 10−³T + R T² 0.121x105 T²
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